jQuery jquery用类查找下一个元素
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/1793944/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
jquery find next element with class
提问by Loony2nz
I'm trying to find the next element with a class of "error" and hitting a wall.
我试图找到下一个具有“错误”类的元素并撞墙。
In looking at the demo on jQuery's site, this should work, but doesn't.
在查看 jQuery 站点上的演示时，这应该有效，但没有。
$("button[disabled]").next().text("this button is disabled");
<div>
<button disabled="disabled">First</button>
<span>no overwrite</span>
<span class="error"></span>
</div>
<div>
<button>Second</button>
<span></span>
</div>
<div>
<button disabled="disabled">Third</button>
<span>no overwrite</span>
<span class="error"></span>
</div>
I'm trying to find the span or div or whatever after the element in question, like the button above.
我试图在有问题的元素之后找到 span 或 div 或任何东西，就像上面的按钮一样。
so the disabled button line should read, 'no overwrite this button is diabled'
所以禁用的按钮行应该是“没有覆盖这个按钮被禁用”
I've tried
我试过了
$("button[disabled]").next(".error").text("this button is disabled");
$("button[disabled]").next(".error").text("this button is disabled");
to no avail.
无济于事。
回答by PetersenDidIt
The problem is that your using the next traversing function rather than nextAll
问题是您使用下一个遍历函数而不是nextAll
$("button[disabled]").nextAll(".error").text("this button is disabled");
When you use next its just looking at the "next" element which is
当您使用 next 时，它只是查看“next”元素
<span>no overwrite</span>
Next all looks at all siblings that are next
Next all 查看接下来的所有兄弟姐妹
回答by Sinan
Try this:
尝试这个：
$("button[disabled=disabled]").parent().find("span.error").text("this button is disabled");
hope it helps. Sinan.
希望能帮助到你。思南。
回答by cletus
next()won't work in this case because it has to be a sibling for that to work. In this case you need:
next()在这种情况下不起作用，因为它必须是兄弟姐妹才能工作。在这种情况下，您需要：
$("button[disabled]").parent().nextAll()
.find("span.error:first").text("this button is disabled");
