python PyQt，Qwidget 上的点击动作
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PyQt, click action on Qwidget
提问by Lopoc
I've this simple problem, I can grab the event of a click on button, but now I need to handle a click over a widget, here is part of the code:
我有这个简单的问题，我可以抓住点击按钮的事件，但现在我需要处理对小部件的点击，这是代码的一部分：
self.widget = QtGui.QWidget(self)
self.widget.setStyleSheet("QWidget { background-color: %s }" % color.name())
self.widget.setGeometry(150, 22, 50, 50)
self.connect(???)
well, what should i put in the ??? to grab a click action over the created widget? thank in advanced
好吧，我应该在里面放什么？？？在创建的小部件上抓取点击动作？提前致谢
回答by Ja8zyjits
you can try this i found this from this blog site's comment box from Jared GlassIt was working fine for me
你可以试试这个我是从这个博客网站的评论框中找到的，来自 Jared Glass这对我来说很好用
self.widget.mouseReleaseEvent=self.myfunction
or
或者
self.widget.mouseReleaseEvent=lambda event:print 'working'
or
或者
self.widget.mouseReleaseEvent=lambda event,my_variable:self.myfunction(event,my_variable)
only the last example is what i have written on my own rest all have been mentioned in http://popdevelop.com/2010/05/an-example-on-how-to-make-qlabel-clickable/. The last code helps you to pass any variables eg:widget name or widget number if multiple widgets exists.
只有最后一个例子是我自己写的，所有都在http://popdevelop.com/2010/05/an-example-on-how-to-make-qlabel-clickable/ 中提到。如果存在多个小部件，最后一个代码可帮助您传递任何变量，例如：小部件名称或小部件编号。
回答by Jesse Aldridge
Use mousePressEvent instead.
请改用 mousePressEvent。
import sys
from PyQt4.QtGui import QWidget, QApplication
class MyWidget(QWidget):
def mousePressEvent(self, event):
print "clicked"
app = QApplication(sys.argv)
widget = MyWidget()
widget.show()
app.exec_()
