如何在 Python 中将数字转换为单词
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How to Convert numbers to Words in Python
提问by user1919840
I need to turn numbers from 1 - 99 into words. This is what I got so far:
我需要将数字从 1 - 99 转换为单词。这是我到目前为止得到的：
num2words1 = {1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', \
6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine', 10: 'Ten', \
11: 'Eleven', 12: 'Twelve', 13: 'Thirteen', 14: 'Fourteen', \
15: 'Fifteen', 16: 'Sixteen', 17: 'Seventeen', 18: 'Eighteen', 19: 'Nineteen'}
num2words2 = ['Twenty', 'Thirty', 'Forty', 'Fifty', 'Sixty', 'Seventy', 'Eighty', 'Ninety']
def number(Number):
if (Number > 1) or (Number < 19):
return (num2words1[Number])
elif (Number > 20) or (Number < 99):
return (num2words2[Number])
else:
print("Number Out Of Range")
main()
def main():
num = eval(input("Please enter a number between 0 and 99: "))
number(num)
main()
Now, the BIGGEST problem that I have so far is that the if, elif and else statements DO NOT seem to work. Only the first if statement runs.
现在，到目前为止我遇到的最大问题是 if、elif 和 else 语句似乎不起作用。只有第一个 if 语句运行。
The second problem is creating the string version of the numbers from 20-99....
第二个问题是创建 20-99 数字的字符串版本......
Please help, thanks in advance.
请帮忙，提前致谢。
P.S. Yes, I know about the num2word library, but I am not allowed to use it.
PS 是的，我知道 num2word 库，但我不允许使用它。
采纳答案by Martijn Pieters
Your first statement logic is incorrect. Unless Numberis 1 or smaller, that statement is alwaysTrue; 200 is greater than 1 as well.
您的第一个语句逻辑不正确。除非Number是 1 或更小，否则该语句始终为真；200 也大于 1。
Use andinstead, and include 1in the acceptable values:
改用and并包含1在可接受的值中：
if (Number >= 1) and (Number <= 19):
You could use chaining as well:
您也可以使用链接：
if 1 <= Number <= 19:
For numbers of 20 or larger, use divmod()to get both the number of tens and the remainder:
对于 20 或更大的数字，使用divmod()来获得十的数量和余数：
tens, remainder = divmod(Number, 10)
Demo:
演示：
>>> divmod(42, 10)
(4, 2)
then use those values to build your number from the parts:
然后使用这些值从零件中构建您的数字：
return num2words2[tens - 2] + '-' + num2words1[below_ten]
Don't forget to account for cases when the number is above 20 and doesn't have a remainder from the divmod operation:
不要忘记考虑数字大于 20 并且没有来自 divmod 操作的余数的情况：
return num2words2[tens - 2] + '-' + num2words1[remainder] if remainder else num2words2[tens - 2]
All put together:
全部放在一起：
def number(Number):
if 0 <= Number <= 19:
return num2words1[Number]
elif 20 <= Number <= 99:
tens, remainder = divmod(Number, 10)
return num2words2[tens - 2] + '-' + num2words1[remainder] if remainder else num2words2[tens - 2]
else:
print('Number out of implemented range of numbers.')
回答by yemu
if Number > 19 and Number < 99:
textNumber = str(Number)
firstDigit, secondDigit = textNumber
firstWord = num2words2[int(firstDigit)]
secondWord = num2words1[int(secondDigit)]
word = firstWord + secondWord
if Number <20 and Number > 0:
word = num2words1[Number]
if Number > 99:
error
回答by bcollins
I've been also converting numbers to words for some fuzzy matching routines. I used a library called inflect I forked off pwdyson which worked awesome:
我也一直在将数字转换为一些模糊匹配例程的单词。我使用了一个名为 inflect 的库，我分叉了 pwdyson，它工作得很棒：
回答by dansalmo
You can make this much simpler by using one dictionary and a try/except clause like this:
您可以通过使用一个字典和一个像这样的 try/except 子句来使这变得更简单：
num2words = {1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', \
6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine', 10: 'Ten', \
11: 'Eleven', 12: 'Twelve', 13: 'Thirteen', 14: 'Fourteen', \
15: 'Fifteen', 16: 'Sixteen', 17: 'Seventeen', 18: 'Eighteen', \
19: 'Nineteen', 20: 'Twenty', 30: 'Thirty', 40: 'Forty', \
50: 'Fifty', 60: 'Sixty', 70: 'Seventy', 80: 'Eighty', \
90: 'Ninety', 0: 'Zero'}
>>> def n2w(n):
try:
print num2words[n]
except KeyError:
try:
print num2words[n-n%10] + num2words[n%10].lower()
except KeyError:
print 'Number out of range'
>>> n2w(0)
Zero
>>> n2w(13)
Thirteen
>>> n2w(91)
Ninetyone
>>> n2w(21)
Twentyone
>>> n2w(33)
Thirtythree
回答by Jake
recursively:
递归地：
num2words = {1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', \
6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine', 10: 'Ten', \
11: 'Eleven', 12: 'Twelve', 13: 'Thirteen', 14: 'Fourteen', \
15: 'Fifteen', 16: 'Sixteen', 17: 'Seventeen', 18: 'Eighteen', 19: 'Nineteen'}
num2words2 = ['Twenty', 'Thirty', 'Forty', 'Fifty', 'Sixty', 'Seventy', 'Eighty', 'Ninety']
def spell(num):
if num == 0:
return ""
if num < 20:
return (num2words[num])
elif num < 100:
ray = divmod(num,10)
return (num2words2[ray[0]-2]+" "+spell(ray[1]))
elif num <1000:
ray = divmod(num,100)
if ray[1] == 0:
mid = " hundred"
else:
mid =" hundred and "
return(num2words[ray[0]]+mid+spell(ray[1]))
回答by CQ92
import math
number = int(input("Enter number to print: "))
number_list = ["zero","one","two","three","four","five","six","seven","eight","nine"]
teen_list = ["ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"]
decades_list =["twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"]
if number <= 9:
print(number_list[number].capitalize())
elif number >= 10 and number <= 19:
tens = number % 10
print(teen_list[tens].capitalize())
elif number > 19 and number <= 99:
ones = math.floor(number/10)
twos = ones - 2
tens = number % 10
if tens == 0:
print(decades_list[twos].capitalize())
elif tens != 0:
print(decades_list[twos].capitalize() + " " + number_list[tens])
回答by Ajesh DS
This Did the job for me(Python 2.x)
这对我有用（Python 2.x）
nums = {1:"One", 2:"Two", 3:"Three" ,4:"Four", 5:"Five", 6:"Six", 7:"Seven", 8:"Eight",\
9:"Nine", 0:"Zero", 10:"Ten", 11:"Eleven", 12:"Tweleve" , 13:"Thirteen", 14:"Fourteen", \
15: "Fifteen", 16:"Sixteen", 17:"Seventeen", 18:"Eighteen", 19:"Nineteen", 20:"Twenty", 30:"Thirty", 40:"Forty", 50:"Fifty",\
60:"Sixty", 70:"Seventy", 80:"Eighty", 90:"Ninety"}
num = input("Enter a number: ")
# To convert three digit number into words
if 100 <= num < 1000:
a = num / 100
b = num % 100
c = b / 10
d = b % 10
if c == 1 :
print nums[a] + "hundred" , nums[b]
elif c == 0:
print nums[a] + "hundred" , nums[d]
else:
c *= 10
if d == 0:
print nums[a] + "hundred", nums[c]
else:
print nums[a] + "hundred" , nums[c], nums[d]
# to convert two digit number into words
elif 0 <= num < 100:
a = num / 10
b = num % 10
if a == 1:
print nums[num]
else:
a *= 10
print nums[a], nums[b]
回答by user3515136
def giveText(num):
pairs={1:'one',2:'two',3:'three',4:'four',5:'five',6:'six',7:'seven',8:'eight',9:'nine',10:'ten',
11:'eleven',12:'twelve',13:'thirteen',14:'fourteen',15:'fifteen',16:'sixteen',17:'seventeen',18:'eighteen',19:'nineteen',20:'twenty',
30:'thirty',40:'fourty',50:'fifty',60:'sixty',70:'seventy',80:'eighty',90:'ninety',0:''} # this and above 2 lines are actually single line
return pairs[num]
def toText(num,unit):
n=int(num)# this line can be removed
ans=""
if n <=20:
ans= giveText(n)
else:
ans= giveText(n-(n%10))+" "+giveText((n%10))
ans=ans.strip()
if len(ans)>0:
return " "+ans+" "+unit
else:
return " "
num="99,99,99,999"# use raw_input()
num=num.replace(",","")# to remove ','
try:
num=str(int(num)) # to check valid number
except:
print "Invalid"
exit()
while len(num)<9: # i want fix length so no need to check it again
num="0"+num
ans=toText( num[0:2],"Crore")+toText(num[2:4],"Lakh")+toText(num[4:6],"Thousand")+toText(num[6:7],"Hundred")+toText(num[7:9],"")
print ans.strip()
回答by Emmanuel Mtali
回答by Srinivas Balina
num2words = {1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', \
6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine', 10: 'Ten', \
11: 'Eleven', 12: 'Twelve', 13: 'Thirteen', 14: 'Fourteen', \
15: 'Fifteen', 16: 'Sixteen', 17: 'Seventeen', 18: 'Eighteen', \
19: 'Nineteen', 20: 'Twenty', 30: 'Thirty', 40: 'Forty', \
50: 'Fifty', 60: 'Sixty', 70: 'Seventy', 80: 'Eighty', \
90: 'Ninety', 0: 'Zero'}
def n2w(n):
try:
return num2words[n]
except KeyError:
try:
return num2words[n-n%10] + num2words[n%10].lower()
except KeyError:
try:
if(n>=100 and n<=999):
w=''
w=w+str(n2w(int(n/100)))+'Hundred'
n=n-(int(n/100)*100)
if(n>0):
w=w+'And'+n2w(n)
return w
elif(n>=1000):
w=''
w=w+n2w(int(n/1000))+'Thousand'
n=n-int((n/1000))*1000
if(n>0 and n<100):
w=w+'And'+n2w(n)
if(n>=100):
w=w+n2w(int(n/100))+'Hundred'
n=n-(int(n/100)*100)
if(n>0):
w=w+'And'+n2w(n)
return w
except KeyError:
return 'Ayyao'
for i in range(0,99999):
print(n2w(i))
