ios 如何从 int 创建 NSIndexPath？
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How to create an NSIndexPath from an int?
提问by Deepak R
Error message:
错误信息：
cast of 'int' to "NSIndexPath *' is disallowed with ARC
ARC 不允许将“int”转换为“NSIndexPath *”
Code:
代码：
NSInteger CurrentIndex;
[self tableView:(UITableView *)horizontalTableView1 didSelectRowAtIndexPath:(NSIndexPath *)int_CurrentIndex];
How do I fix this error?
我该如何解决这个错误？
回答by TheTiger
You can't cast an intvariable to an NSIndexPathdirectly. But you can make an NSIndexPathfrom an intvariable.
您不能直接将int变量强制转换为 an NSIndexPath。但是你可以NSIndexPath从一个int变量中创建一个。
You need a sectionindex and rowindex to make an NSIndexPath. If your UITableViewhas only one sectionthen:
您需要一个section索引和row索引来制作NSIndexPath. 如果你UITableView只有一个，section那么：
Objective-C
目标-C
NSIndexPath *indexPath = [NSIndexPath indexPathForRow:rowIndex inSection:0];
Swift
迅速
let indexPath: NSIndexPath = NSIndexPath(forRow: rowIndex, inSection: 0)
Swift 4
斯威夫特 4
let indexPath = IndexPath(row: rowIndex, section: 0)
回答by Chandramani
Swift 3.0
Swift 3.0
let indexPath : IndexPath = IndexPath(item: currentIndex, section: 0)
