Java 我需要一个简单的命令行程序来使用 XSL 样式表转换 XML
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I need a simple command line program to transform XML using an XSL Stylesheet
提问by
I am on OSX Snow Leopard (10.6.2) I can install anything I need to. I would preferably like a Python or Java solution. I have searched on Google and found lots of information on writing my own program to do this, but this is a just a quick and dirty experiment so I don't want to invest a lot of time on writing a bunch of code to do this, I am sure someone else has done this already.
我使用的是 OSX Snow Leopard (10.6.2) 我可以安装我需要的任何东西。我更喜欢 Python 或 Java 解决方案。我在谷歌上搜索并找到了很多关于编写我自己的程序来做到这一点的信息，但这只是一个快速而肮脏的实验，所以我不想投入大量时间来编写一堆代码来做到这一点，我相信其他人已经这样做了。
This is off-topic now, do not use this question as an example of why your recommendations request is on topic, it is not. I apologize, but my Google-Foo was failing me the day I asked this 4 years ago!
现在这是题外话，不要使用这个问题作为为什么你的推荐请求是主题的例子，它不是。我道歉，但我的 Google-Foo 在我 4 年前问这个问题的那天让我失望了！
采纳答案by nbeyer
Have you tried 'xsltproc'? It's probably already installed.
你试过' xsltproc'吗？它可能已经安装了。
回答by nosklo
Use lxml. It is very easy to use and very fast. It can work with XPath and includes a XSLT transformer.
回答by Jon
If I assume correctly that you want to supply a stylesheet and an XML document then Xalan-J has a command line feature you can use to do this:
如果我正确地假设您想要提供样式表和 XML 文档，那么 Xalan-J 有一个命令行功能，您可以使用它来执行此操作：
http://xml.apache.org/xalan-j/commandline.html
http://xml.apache.org/xalan-j/commandline.html
which can be invoked with:
可以通过以下方式调用：
java org.apache.xalan.xslt.Process -IN foo.xml -XSL foo.xsl -OUT foo.out
回答by Brian Agnew
Have you seen XMLStarlet(an XML command line toolset) ? It does lots of XML-related querying transformation, and in particular:
您见过XMLStarlet（一个 XML 命令行工具集）吗？它做了很多与 XML 相关的查询转换，特别是：
xml tr --help
XMLStarlet Toolkit: Transform XML document(s) using XSLT
Usage: xml tr [<options>] <xsl-file> {-p|-s <name>=<value>} [ <xml-file-or-uri> ... ]
where
<xsl-file> - main XSLT stylesheet for transformation
<xml-file> - input XML document file name (stdin is used if missing)
<name>=<value> - name and value of the parameter passed to XSLT processor
-p - parameter is XPATH expression ("'string'" to quote string)
-s - parameter is a string literal
Further documentation here.
进一步的文档在这里。
回答by Will McCutchen
回答by Thorbj?rn Ravn Andersen
I have used Saxon 6.5 for years for command line transformations. (Java, XSLT 1)
我多年来一直使用 Saxon 6.5 进行命令行转换。（Java，XSLT 1）
An excellent fallback if a native solution is not available.
如果本机解决方案不可用，这是一个很好的后备方案。
回答by akostadinov
see this questionfor another solution with com.sun.org.apache.xalan.internal.xsltc.cmdline.Transform. But I noticed some weirdness with namespaces compared to xalan processing. Be aware behavior might be non standard.
有关com.sun.org.apache.xalan.internal.xsltc.cmdline.Transform 的另一个解决方案，请参阅此问题。但是我注意到与 xalan 处理相比，命名空间有些奇怪。请注意行为可能是非标准的。
Also you know, internal java classes are not good to rely on.
你也知道，内部 java 类不好依赖。
