laravel Eloquent morphOne 关系不限于一种关系
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Eloquent morphOne relationship doesn't limit to one relation
提问by Keet
I am having a issue with an Eloquent morphOnerelationship where it is creating new entries rather than updating the one that already exists.
我遇到了 EloquentmorphOne关系的问题，它正在创建新条目而不是更新已经存在的条目。
Basically I have a number of models (for example, let's say Personand Building) that both need a location, so I have created a Locationmodel:
基本上我有许多模型（例如，假设Person和Building）都需要一个位置，所以我创建了一个Location模型：
class Location extends Eloquent {
public function locationable()
{
return $this->morphTo();
}
}
Then in my other models I have this:
然后在我的其他模型中，我有这个：
class Person extends Eloquent {
// ...
/**
* Get the person's location
*
* @return Location
*/
public function location()
{
return $this->morphOne('Location', 'locationable');
}
// ...
class Building extends Eloquent {
// ...
/**
* Get the building's location
*
* @return Location
*/
public function location()
{
return $this->morphOne('Location', 'locationable');
}
// ...
When I run the following test code, it creates the location entry fine, but if I repeat it, it creates more entries.
当我运行以下测试代码时，它会很好地创建位置条目，但如果我重复它，它会创建更多条目。
$person = Person::first();
$loc = new Location;
$loc->lat = "123";
$loc->lng = "321";
$person->location()->save($loc);
Am I doing something wrong here? I would have expected morphOneto constrain this to one entry per type, so the last entry in the table below should not exist:
我在这里做错了吗？我本来希望将morphOne其限制为每种类型的一个条目，因此下表中的最后一个条目不应该存在：
+---------------------+--------------------------+
| locationable_id | locationable_type |
+---------------------+--------------------------+
| 2 | Building |
| 3 | Building |
| 2 | Person |
| 2 | Building |
+---------------------+--------------------------+
回答by Murwa
Maybe I'm late for the party, but this worked for me!
也许我参加聚会迟到了，但这对我有用！
# Do we have location already?
if($person->location) {
return $person->location()->update($location);
}
return $person->location()->create($location);
回答by Assarte
Based on my very current experiences, this solution should be works
根据我目前的经验，这个解决方案应该有效
Creation or replace old by new Location model instance:
用新的 Location 模型实例创建或替换旧的：
$person = Person::first();
$loc = new Location;
$loc->lat = "123";
$loc->lng = "321";
$loc->save();
$person->location()->associate($loc);
$person->save();
Update:
更新：
$person = Person::first();
$person->location->lat = "123";
$person->location->lng = "321";
$person->location->save();
$person->save();
I spent many days for finding out this solution. Hope they would document it much better officially.
我花了很多天来找出这个解决方案。希望他们能更好地正式记录它。
回答by sisou
Actually, by calling
实际上，通过调用
$loc = new Location;
you are, by definition, creating a new location!
根据定义，您正在创建一个新位置！
Calling
打电话
$person->location()->save($loc);
doesn't help either.
也没有帮助。
IF you want to updatea location, you need to find the location, update it's values and then save it. Independently from the parent model:
如果你想更新一个位置，你需要找到这个位置，更新它的值然后保存它。独立于父模型：
$person = Person::first();
$loc = $person->location;
$loc->lat = "123";
$loc->lng = "321";
$loc->save();
Done.
完毕。
