Javascript 一位或两位数字正则表达式
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One or two numeric digits Regex
提问by CBuzatu
I have the below code. It works only when I have 2 digits. If I have 1 digit doesn't work. I want to work in both cases: one or two digit.var numberRegex = /^[1-9][0-9]$/;
I've tried something like this but unfortunately doesn't work:var numberRegex = /^[1-9]?[1-9][0-9]$/;
Thanks for support.
我有以下代码。仅当我有 2 位数字时才有效。如果我有 1 位数字不起作用。我想在两种情况下工作：一位或两位数。var numberRegex = /^[1-9][0-9]$/;
我试过这样的事情，但不幸的是不起作用：var numberRegex = /^[1-9]?[1-9][0-9]$/;
感谢支持。
回答by Joel Etherton
Try this one out:
试试这个：
/^\d{1,2}$/;
Reading what you have it looks like you don't want to accept numbers like 01.
阅读您拥有的内容，您似乎不想接受01.
/^\d{1}|[1-9]\d{1}$/;
回答by Vishak Kavalur
Try this.
尝试这个。
/^[0-9]|[0-9][0-9]$/
This should do the job. Using an Or operator does it.
这应该可以完成工作。使用 Or 运算符即可。
回答by Ozz
This works:
这有效：
/^([0-9]{0,1}([1-9][0-9]){0,2})$/
回答by Darshana
try this regex: /^[1-9]\d{0,1}$/
试试这个正则表达式： /^[1-9]\d{0,1}$/
