Python 将 APIView 添加到 Django REST Framework 可浏览 API
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/28730109/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Adding a APIView to Django REST Framework Browsable API
提问by Jae
I've been developing a REST backend with the Django REST Framework.
However, I'm having trouble adding a APIView instance to the web browsable API.
我一直在使用 Django REST 框架开发 REST 后端。
但是，我无法将 APIView 实例添加到 Web 可浏览 API。
The documentationand the previous answersuggests that all I have to do is add a docstring.
It did not work for me.
该文件与以前的答案表明，所有我需要做的就是添加一个文档字符串。
它对我不起作用。
I'm under the assumption that the browsable API only displays Viewset endpoints are registered with the router.
If this is so, how can I register APIView classes to the router?
我假设可浏览的 API 仅显示已向路由器注册的 Viewset 端点。
如果是这样，我如何将 APIView 类注册到路由器？
Below is my current router code:
以下是我当前的路由器代码：
router = DefaultRouter(trailing_slash=False)
router.register(r'tokens', TokenViewSet, base_name='token')
urlpatterns = patterns('',
url(r'^admin/', include(admin.site.urls)),
url(r'^api/', include(router.urls)),
url(r'^api/register$', RegisterUser.as_view(), name='register_user'),
url(r'^api/auth$', ObtainAuthToken.as_view(), name='obtain_token'),
url(r'^api/me$', ObtainProfile.as_view(), name='obtain_profile'),
url(r'^api/recover$', FindUsername.as_view(), name='recover_username'),
)
Currently, only the Token endpoint shows up.
目前，仅显示 Token 端点。
Thank you.
谢谢你。
回答by nmgeek
I believe the line that includes the router.urls is 'preempting' other urls starting with api. Try changing,
我相信包含 router.urls 的行是“抢占”以api开头的其他 url 。尝试改变，
url(r'^api/', include(router.urls)),
to
到
url(r'^tokenapi/', include(router.urls)),
If that works then try moving the line with includeto be the last line in the url patterns list and changing tokenapiback to api.
如果可行，则尝试将包含 include的行移动到 url 模式列表中的最后一行，并将tokenapi更改回api。
urlpatterns = patterns('',
url(r'^admin/', include(admin.site.urls)),
url(r'^api/register$', RegisterUser.as_view(), name='register_user'),
url(r'^api/auth$', ObtainAuthToken.as_view(), name='obtain_token'),
url(r'^api/me$', ObtainProfile.as_view(), name='obtain_profile'),
url(r'^api/recover$', FindUsername.as_view(), name='recover_username'),
url(r'^api/', include(router.urls)),
)
回答by flytofuture
Routers aren't designed for normal views. You need use ViewSet if you want register you url to your router.
路由器不是为普通视图设计的。如果要将 url 注册到路由器，则需要使用 ViewSet。
I have the same question here. Maybe you can ref it: How can I register a single view (not a viewset) on my router?
我在这里也有同样的问题。也许您可以参考它： 如何在路由器上注册单个视图（而不是视图集）？
