C++ 如何使指针指向二维数组的任何数组元素？
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How to make a pointer point to any array element of a 2D array?
提问by Vishnu Vivek
Coming straight to the point,
直接进入正题，
I want the character pointer pto point to the only array element that contains the character 'T'.
我希望字符指针p指向包含字符 ' T'的唯一数组元素。
char a[100][100];
char *p;
for(int i=0;i<4;i++)
for(int j=0;j<4;j++)
if(a[i][j] == 'T')
p = a[i][j];
P.S. I tried with various combinations of *, **, etc but nothing seems to work.
PS我已经尝试过的各种组合*，**等，但似乎没有任何工作。
回答by Bart Friederichs
Use its address:
使用它的地址：
char a[100][100];
char *p;
for(int i=0;i<4;i++)
for(int j=0;j<4;j++)
if(a[i][j] == 'T')
p = &a[i][j];
a[i][j]is of type charand pis of type char *, which holds an address. To get the address of a variable, prepend it with &.
a[i][j]is of typechar和pis of type char *，它保存一个地址。要获取变量的地址，请在其前面加上&.
The *operator on a pointer works the other way round. If you would want to get the 'T'back, you'd use:
*指针上的运算符以相反的方式工作。如果你想'T'找回，你会使用：
char theT = *p;
回答by Manolis Ragkousis
there is another way to get it
还有另一种方法可以得到它
char a[100][100];
char *p;
for(int i=0;i<4;i++)
for(int j=0;j<4;j++)
if(a[i][j] == 'T')
p = a[i]+j;
By writing p = a[i]+j;you actually say, We have a pointer at the begging of an array called a[i]and you point to the position that is jtimes away from the begging of that array!
通过写p = a[i]+j;你实际上说，我们有一个指针指向一个名为a[i]的数组，你指向距离该数组的请求j倍的位置！
回答by Adnan Akbar
change the if part as follows
更改 if 部分如下
if(a[i][j] == 'T' ) {
p = (char *) &a[i][j];
i = 4; break;
}
