Python 如何在 Pygame 中将图像缩放到屏幕大小
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How to scale images to screen size in Pygame
提问by Ilmiont
I was wondering how I would go about scaling the size of images in pygameprojects to the resolution of the screen. For example, envisage the following scenario assuming windowed display mode for the time being; I assume full screen will be the same:
我想知道如何将pygame项目中的图像大小缩放到屏幕分辨率。例如，假设以下场景暂时假设窗口显示模式；我假设全屏将是相同的：
I have a
1600x900background image which of course displays natively in a1600x900windowIn a
1280x720window I can obviously just scale this images' rect to1280x720What happens, however if I need to add, say a
300x300 pximage atx,y 1440,860(example sizes) that is sized to fit with the original1600x900background? Of course for the1600x900I can of course use the image natively but what about the smaller/larger window sizes?
我有一个
1600x900背景图像，它当然显示在一个1600x900窗口中在一个
1280x720窗口中，我显然可以将这个图像的矩形缩放到1280x720但是，如果我需要添加（示例尺寸）的
300x300 px图像，该图像的x,y 1440,860尺寸适合原始1600x900背景，会发生什么情况？当然，对于1600x900我当然可以本地使用图像但是更小/更大的窗口大小呢？
Basically, how do I scale images to the window size and then position them accordingly? I guess there must be a REALLY easy automated method but right now I can't figure it out and quite frankly haven't got time to search for it...
基本上，如何将图像缩放到窗口大小，然后相应地定位它们？我想一定有一个非常简单的自动化方法，但现在我无法弄清楚，坦率地说，没有时间去寻找它......
Thanks in advance, Ilmiont
提前致谢， Ilmiont
回答by unutbu
You can scale the image with pygame.transform.scale:
您可以使用以下方法缩放图像pygame.transform.scale：
import pygame
picture = pygame.image.load(filename)
picture = pygame.transform.scale(picture, (1280, 720))
You can then get the bounding rectangle of picturewith
然后，您可以得到的边框picture与
rect = picture.get_rect()
and move the picture with
并移动图片
rect = rect.move((x, y))
screen.blit(picture, rect)
where screenwas set with something like
在哪里screen设置了类似的东西
screen = pygame.display.set_mode((1600, 900))
To allow your widgets to adjust to various screen sizes, you could make the display resizable:
为了让您的小部件适应各种屏幕尺寸，您可以调整显示大小：
import os
import pygame
from pygame.locals import *
pygame.init()
screen = pygame.display.set_mode((500, 500), HWSURFACE | DOUBLEBUF | RESIZABLE)
pic = pygame.image.load("image.png")
screen.blit(pygame.transform.scale(pic, (500, 500)), (0, 0))
pygame.display.flip()
while True:
pygame.event.pump()
event = pygame.event.wait()
if event.type == QUIT:
pygame.display.quit()
elif event.type == VIDEORESIZE:
screen = pygame.display.set_mode(
event.dict['size'], HWSURFACE | DOUBLEBUF | RESIZABLE)
screen.blit(pygame.transform.scale(pic, event.dict['size']), (0, 0))
pygame.display.flip()
回答by furas
If you scale 1600x900 to 1280x720 you have
如果您将 1600x900 缩放到 1280x720
scale_x = 1280.0/1600
scale_y = 720.0/900
Than you can use it to find button size, and button position
比您可以使用它来查找按钮大小和按钮位置
button_width = 300 * scale_x
button_height = 300 * scale_y
button_x = 1440 * scale_x
button_y = 860 * scale_y
If you scale 1280x720 to 1600x900 you have
如果您将 1280x720 缩放到 1600x900
scale_x = 1600.0/1280
scale_y = 900.0/720
and rest is the same.
休息是一样的。
I add .0to value to make float- otherwise scale_x, scale_ywill be rounded to integer- in this example to 0(zero) (Python 2.x)
我添加.0值以生成float- 否则scale_x，scale_y将四舍五入为integer- 在本例中为0（零）（Python 2.x）
