bash 在执行shell脚本时，如何知道它正在执行的行号，
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While executing shell scripts, how to know which line number it's executing,
提问by anish
While executing shell scripts, how to know which line number it's executing, do have write a wrapper , where i can execute a shell scripts from a shell scripts and to know which line number it's executing.
在执行 shell 脚本时，如何知道它正在执行的行号，确实编写了一个包装器，我可以在其中从 shell 脚本执行 shell 脚本并知道它正在执行的行号。
回答by Charles Duffy
You can set the PS4variable to cause set -xoutput to include the line number:
您可以设置PS4变量以使set -x输出包含行号：
PS4=':${LINENO}+'
set -x
This will put the line number before each line as it executes:
这将在执行时将行号放在每行之前：
:4+command here
:5+other command
It's important to have some sigil character (such as a +in my examples) after your variable expansions in PS4, because that last character is repeated to show nesting depth. That is, if you call a function, and that function invokes a command, the output from set -xwill report it like so:
+在 中的变量扩展之后有一些符号字符（例如我的示例中的 a）很重要PS4，因为重复最后一个字符以显示嵌套深度。也就是说，如果您调用一个函数，并且该函数调用一个命令，则输出set -x将报告如下：
:3+++command run within a function called from a function
:8++command run within a function
:19+line after the function was called
If multiple files are involved in running your script, you might want to include the BASH_SOURCEvariable as opposed to only LINENO(assuming this really is a bash script, as opposed to /bin/sh-- be sure your script starts with #!/bin/bash!):
如果运行脚本涉及多个文件，则您可能希望包含BASH_SOURCE变量而不是仅包含变量LINENO（假设这确实是一个 bash 脚本，而不是/bin/sh-- 请确保您的脚本以#!/bin/bash!开头）：
PS4=':${BASH_SOURCE}:${LINENO}+'
set -x
回答by Paused until further notice.
Bash has a special variable $LINENOwhich does what you want.
Bash 有一个特殊的变量$LINENO可以做你想要的。
#!/bin/bash
echo "$LINENO"
echo "$LINENO"
echo "$LINENO"
Demo:
演示：
$ ./lineno
2
3
4
