Javascript 检查数组是否包含另一个数组的所有元素
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Check if array contains all elements of another array
提问by lakshay bakshi
Target array [1,2,3]
目标阵列 [1,2,3]
array1 = [1,2,3]; //return true
array2 = [1,2,3,4]; //return true
array3 = [1,2] //return false
i am not getting how to achieve this or may be need to use custom login in this. I have used some and include but that doesn't work for me.
我不知道如何实现这一点，或者可能需要在此使用自定义登录。我已经使用了一些并包含，但这对我不起作用。
回答by Mohammad Usman
You can use .every()and .includes()methods:
您可以使用.every()和.includes()方法：
let array1 = [1,2,3],
array2 = [1,2,3,4],
array3 = [1,2];
let checker = (arr, target) => target.every(v => arr.includes(v));
console.log(checker(array2, array1));
console.log(checker(array3, array1));回答by Mamun
You can try with Array.prototype.every():
您可以尝试Array.prototype.every()：
The
every()method tests whether all elements in the array pass the test implemented by the provided function.
该
every()方法测试数组中的所有元素是否通过提供的函数实现的测试。
and Array.prototype.includes():
The
includes()method determines whether an array includes a certain element, returning true or false as appropriate.
该
includes()方法确定数组是否包含某个元素，根据情况返回 true 或 false。
var mainArr = [1,2,3];
function isTrue(arr, arr2){
return arr.every(i => arr2.includes(i));
}
console.log(isTrue(mainArr, [1,2,3]));
console.log(isTrue(mainArr, [1,2,3,4]));
console.log(isTrue(mainArr, [1,2]));回答by zetawars
If you are using ES5, then you can simply do this.
如果您使用的是 ES5，那么您可以简单地执行此操作。
targetArray =[1,2,3];
array1 = [1,2,3]; //return true
array2 = [1,2,3,4]; //return true
array3 = [1,2] //return false
console.log(targetArray.every(function(val) { return array1.indexOf(val) >= 0; })); //true
console.log(targetArray.every(function(val) { return array2.indexOf(val) >= 0; })); // true
console.log(targetArray.every(function(val) { return array3.indexOf(val) >= 0; }));// false
回答by Pankaj Revagade
I used Purely Javascript.
我使用纯 Javascript。
function checkElementsinArray(fixedArray,inputArray)
{
var fixedArraylen = fixedArray.length;
var inputArraylen = inputArray.length;
if(fixedArraylen<=inputArraylen)
{
for(var i=0;i<fixedArraylen;i++)
{
if(!(inputArray.indexOf(fixedArray[i])>=0))
{
return false;
}
}
}
else
{
return false;
}
return true;
}
console.log(checkElementsinArray([1,2,3], [1,2,3]));
console.log(checkElementsinArray([1,2,3], [1,2,3,4]));
console.log(checkElementsinArray([1,2,3], [1,2]));
