ios 如何在 UITextView 中显示可点击的链接
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How to display clickable links in UITextView
提问by jhk727
I am trying to display an attributed string in a UITextview with clickable links. I've created a simple test project to see where I'm going wrong and still can't figure it out. I've tried enabling user interaction and setting the shouldInteractWithURLs delegate method, but it's still not working. Here's my code (for a view controller that only contains a textview)
我试图在带有可点击链接的 UITextview 中显示属性字符串。我创建了一个简单的测试项目来查看我哪里出错了,但仍然无法弄清楚。我已经尝试启用用户交互并设置 shouldInteractWithURLs 委托方法,但它仍然无法正常工作。这是我的代码(对于仅包含 textview 的视图控制器)
@IBOutlet weak var textView: UITextView!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
let string = "Google"
let linkString = NSMutableAttributedString(string: string)
linkString.addAttribute(NSLinkAttributeName, value: NSURL(string: "https://www.google.com")!, range: NSMakeRange(0, string.characters.count))
linkString.addAttribute(NSFontAttributeName, value: UIFont(name: "HelveticaNeue", size: 25.0)!, range: NSMakeRange(0, string.characters.count))
textView.attributedText = linkString
textView.delegate = self
textView.selectable = true
textView.userInteractionEnabled = true
}
And here are the delegate methods I've implemented:
这是我实现的委托方法:
func textViewShouldBeginEditing(textView: UITextView) -> Bool {
return false
}
func textView(textView: UITextView, shouldInteractWithURL URL: NSURL, inRange characterRange: NSRange) -> Bool {
return true
}
This still isn't working. I've searched on this topic and nothing has helped yet. Thanks so much in advance.
这仍然不起作用。我已经搜索过这个主题,但没有任何帮助。非常感谢。
回答by Rashwan L
回答by Maulik Patel
For swift3.0
对于 swift3.0
override func viewDidLoad() {
super.viewDidLoad()
let linkAttributes = [
NSLinkAttributeName: NSURL(string: "http://stalwartitsolution.co.in/luminutri_flow/terms-condition")!
] as [String : Any]
let attributedString = NSMutableAttributedString(string: "Please tick box to confirm you agree to our Terms & Conditions, Privacy Policy, Disclaimer. ")
attributedString.setAttributes(linkAttributes, range: NSMakeRange(44, 18))
attributedString.addAttribute(NSUnderlineStyleAttributeName, value: NSNumber(value: 1), range: NSMakeRange(44, 18))
textview.delegate = self
textview.attributedText = attributedString
textview.linkTextAttributes = [NSForegroundColorAttributeName: UIColor.red]
textview.textColor = UIColor.white
}
func textView(_ textView: UITextView, shouldInteractWith URL: URL, in characterRange: NSRange, interaction: UITextItemInteraction) -> Bool {
return true
}
回答by Jad
Swift 3 iOS 10:Here's Clickable extended UITextView that detect websites inside the textview automatically as long as the link start with www.for example: www.exmaple.comif it exist anywhere in the text will be clickable. Here's the class:
Swift 3 iOS 10:这是可点击的扩展 UITextView,只要链接以www开头,它就会自动检测文本视图中的网站。例如:www.exmaple.com如果它存在于文本中的任何位置,则可点击。这是课程:
import Foundation
import UIKit
public class ClickableTextView:UITextView{
var tap:UITapGestureRecognizer!
override public init(frame: CGRect, textContainer: NSTextContainer?) {
super.init(frame: frame, textContainer: textContainer)
print("init")
setup()
}
required public init?(coder aDecoder: NSCoder) {
super.init(coder: aDecoder)
setup()
}
func setup(){
// Add tap gesture recognizer to Text View
tap = UITapGestureRecognizer(target: self, action: #selector(self.myMethodToHandleTap(sender:)))
// tap.delegate = self
self.addGestureRecognizer(tap)
}
func myMethodToHandleTap(sender: UITapGestureRecognizer){
let myTextView = sender.view as! UITextView
let layoutManager = myTextView.layoutManager
// location of tap in myTextView coordinates and taking the inset into account
var location = sender.location(in: myTextView)
location.x -= myTextView.textContainerInset.left;
location.y -= myTextView.textContainerInset.top;
// character index at tap location
let characterIndex = layoutManager.characterIndex(for: location, in: myTextView.textContainer, fractionOfDistanceBetweenInsertionPoints: nil)
// if index is valid then do something.
if characterIndex < myTextView.textStorage.length {
let orgString = myTextView.attributedText.string
//Find the WWW
var didFind = false
var count:Int = characterIndex
while(count > 2 && didFind == false){
let myRange = NSRange(location: count-1, length: 2)
let substring = (orgString as NSString).substring(with: myRange)
// print(substring,count)
if substring == " w" || (substring == "w." && count == 3){
didFind = true
// print("Did find",count)
var count2 = count
while(count2 < orgString.characters.count){
let myRange = NSRange(location: count2 - 1, length: 2)
let substring = (orgString as NSString).substring(with: myRange)
// print("Did 2",count2,substring)
count2 += 1
//If it was at the end of textView
if count2 == orgString.characters.count {
let length = orgString.characters.count - count
let myRange = NSRange(location: count, length: length)
let substring = (orgString as NSString).substring(with: myRange)
openLink(link: substring)
print("It's a Link",substring)
return
}
//If it's in the middle
if substring.hasSuffix(" "){
let length = count2 - count
let myRange = NSRange(location: count, length: length)
let substring = (orgString as NSString).substring(with: myRange)
openLink(link: substring)
print("It's a Link",substring)
return
}
}
return
}
if substring.hasPrefix(" "){
print("Not a link")
return
}
count -= 1
}
}
}
func openLink(link:String){
if let checkURL = URL(string: "http://\(link.replacingOccurrences(of: " ", with: ""))") {
if UIApplication.shared.canOpenURL(checkURL) {
UIApplication.shared.open(checkURL, options: [:], completionHandler: nil)
print("url successfully opened")
}
} else {
print("invalid url")
}
}
public override func didMoveToWindow() {
if self.window == nil{
self.removeGestureRecognizer(tap)
print("ClickableTextView View removed from")
}
}
}