javascript 正则表达式删除每行开头的空格？
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Regular expression to remove space in the beginning of each line?
提问by kiran
I want to remove space in the beggining of each line.
我想删除每一行开头的空格。
I have data in each line with a set of spaces in the beginning so data appears in the middle, I want to remove spaces in the beginning of each line.
我每行都有数据，开头有一组空格，所以数据出现在中间，我想删除每行开头的空格。
tmp = tmp.replace(/(<([^>]+)>)/g,"")
How can I add the ^\scondition into that replace()?
如何将^\s条件添加到其中replace()？
回答by Kobi
To remove all leading spaces:
要删除所有前导空格：
str = str.replace(/^ +/gm, '');
The regex is quite simple - one or more spaces at the start. The more interesting bits are the flags - /g(global) to replace all matches and not just the first, and /m(multiline) so that the caret matches the beginning of each line, and not just the beginning of the string.
正则表达式非常简单——开头有一个或多个空格。更有趣的位是标志 - /g（全局）替换所有匹配项而不仅仅是第一个，和/m（多行）以便插入符匹配每一行的开头，而不仅仅是字符串的开头。
Working example: http://jsbin.com/oyeci4
工作示例：http: //jsbin.com/oyeci4
回答by Gabriel
var text = " this is a string \n"+
" \t with a much of new lines \n";
text.replace(/^\s*/gm, '');
this supports multiple spaces of different types including tabs.
这支持不同类型的多个空格，包括制表符。
回答by BraedenP
If all you need is to remove one space, then this regex is all you need:
如果您只需要删除一个空格，那么这个正则表达式就是您所需要的：
^\s
So in JavaScript:
所以在 JavaScript 中：
yourString.replace(/(?<=\n) /gm,"");
