Linux 将文件夹中的所有文件重命名为编号列表 1.jpg 2.jpg
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rename all files in folder to numbered list 1.jpg 2.jpg
提问by Yamaha32088
I have a folder full of images with several different random file names to help organize this mess I would like to, in one command rename all of them to a sequential order so if I have 100 files it starts off naming the first file file-1.jpgfile-2.jpgetc. Is this possible in one command?
我有一个文件夹，里面有几个不同的随机文件名来帮助组织这个混乱的图像，我想在一个命令中将它们全部重命名为一个顺序顺序，所以如果我有 100 个文件，它会开始命名第一个文件file-1.jpgfile-2.jpg等。是这可能在一个命令中？
采纳答案by Yamaha32088
I was able to solve my problem by writing a bash script
我能够通过编写 bash 脚本来解决我的问题
#!/bin/sh
num=1
for file in *.jpg; do
mv "$file" "$(printf "%u" $num).jpg"
let num=$num+1
done
回答by Sven Marnach
The most concise command line to do this I can think of is
我能想到的最简洁的命令行是
ls | cat -n | while read n f; do mv "$f" "file-$n.jpg"; done
lslists the files in the current directory and cat -nadds line numbers. The whileloop reads the resulting numbered list of files line by line, stores the line number in the variable nand the filename in the variable fand performs the rename.
ls列出当前目录中的文件并cat -n添加行号。所述while环路逐行读取文件线，存储在变量中的行号的所得到的编号的列表n和在可变的文件名f并进行重命名。
