java 如何重定向到 Servlet 过滤器中的当前页面？
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How do I redirect to the current page in Servlet Filter?
提问by JeffJak
I have a page say: /myapp/test.jsp?queryString=Y. The filter needs to redirect to current page. It should go to /myapp/test.jsp(without the query string). The below seems to bring it to to the context root: /myapp. I am running in WAS6.1.
我有一个页面说： /myapp/test.jsp?queryString=Y。过滤器需要重定向到当前页面。它应该转到/myapp/test.jsp（没有查询字符串）。下面似乎将它带到上下文根： /myapp。我在 WAS6.1 中运行。
public void doFilter(ServletRequest req, ServletResponse resp, FilterChain chain) throws IOException, ServletException {
HttpServletRequest httpReq = (HttpServletRequest) req;
HttpServletResponse httpResp = (HttpServletResponse) resp;
{
boolean blnNeedToRedirect = true;
if (blnNeedToRedirect) {
httpResp.sendRedirect(".");
return;
}
chain.doFilter(req, resp);
}
回答by skaffman
Use HttpServletrequest.getRequestURI. This should work for you:
使用HttpServletrequest.getRequestURI。这应该适合你：
httpResp.sendRedirect(httpReq.getRequestURI());
回答by Hesham Yassin
httpReq.getRequestURI() Gives you the servlet path and it should work as follows. In order to redirect to the same page, run the next command:
httpReq.getRequestURI() 为您提供 servlet 路径，它应该按如下方式工作。为了重定向到同一页面，运行下一个命令：
((HttpServletResponse) httpResp).sendRedirect(httpResp.encodeRedirectURL(httpReq.getRequestURI()));
Another Option is to add the Header Locationwith a status code 302 as follows:
另一种选择是添加Location状态码为 302的 Header ，如下所示：
((HttpServletResponse) httpResp).setStatus(HttpServletResponse.SC_MOVED_TEMPORARILY);
((HttpServletResponse) httpResp).addHeader("Location", request.getRequestURL().toString());
