javascript 如何在json中包含一个php变量并传递给ajax
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How to include a php variable in json and pass to ajax
提问by Nevin
My Code
我的代码
var json = xmlhttp.responseText; //ajax response from my php file
obj = JSON.parse(json);
alert(obj.result);
And in my php code
在我的 php 代码中
$result = 'Hello';
echo '{
"result":"$result",
"count":3
}';
The problem is: when I alert obj.result, it shows "$result", instead of showing Hello.
How can I solve this?
问题是：当我 alert 时obj.result，它显示"$result"，而不是显示Hello。我该如何解决这个问题？
回答by Will Palmer
The basic problem with your example is that $resultis wrapped in single-quotes. So the first solution is to unwrap it, eg:
您的示例的基本问题$result是用单引号括起来。所以第一个解决方案是打开它，例如：
$result = 'Hello';
echo '{
"result":"'.$result.'",
"count":3
}';
But this is still not "good enough", as it is always possible that $resultcould contain a "character itself, resulting in, for example, {"result":""","count":3}, which is still invalid json. The solution is to escape the $resultbefore it is inserted into the json.
但这仍然不够“足够好”，因为它总是可能$result包含一个"字符本身，从而导致，例如，{"result":""","count":3}仍然是无效的 json。解决方案是在将$result其插入到 json 之前对其进行转义。
This is actually very straightforward, using the json_encode()function:
这其实很简单，使用json_encode()函数：
$result = 'Hello';
echo '{
"result":'.json_encode($result).',
"count":3
}';
or, even better, we can have PHP do the entirety of the json encoding itself, by passing in a whole array instead of just $result:
或者，更好的是，我们可以让 PHP 自己完成整个 json 编码，方法是传入一个完整的数组，而不仅仅是$result：
$result = 'Hello';
echo json_encode(array(
'result' => $result,
'count' => 3
));
回答by Gumbo
You should use json_encodeto encode the data properly:
您应该使用json_encode正确编码数据：
$data = array(
"result" => $result,
"count" => 3
);
echo json_encode($data);
回答by ma?ek
You're using single quotes in your echo, therefore no string interpolation is happening
您在回声中使用单引号，因此没有发生字符串插值
use json_encode()
$arr = array(
"result" => $result,
"count" => 3
);
echo json_encode($arr);
As a bonus, json_encodewill properly encode your response!
作为奖励，json_encode将正确编码您的回复！
回答by seangates
Try:
尝试：
$result = 'Hello';
echo '{
"result":"'.$result.'",
"count":3
}';
回答by ZloyPotroh
$result = 'Hello';
$json_array=array(
"result"=>$result,
"count"=>3
)
echo json_encode($json_array);
That's all.
就这样。
