Pandas：数据框字典
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Pandas: Dictionary of Dataframes
提问by Adi
I have a function that I made to analyze experimental data (all individual .txt files)
我有一个用来分析实验数据的函数（所有单独的 .txt 文件）
This function outputs a dictionary ({}) of Pandas Dataframes
此函数输出 Pandas Dataframes 的字典 ({})
Is there a efficient way to iterate over this dictionary and output individual dataframes? Let's say my dictionary is called analysisdict
有没有一种有效的方法来迭代这个字典并输出单个数据帧？假设我的字典叫做 analysisdict
for key in analysisdict.keys():
dfx=pd.concat([analysisdict[key]['X'], analysisdict[key]['Y']], axis=1)
Where dfx would be an individual dataframe. (I'm guessing a second loop might be required? Perhaps I should iterate through a list of df names?)
其中 dfx 将是一个单独的数据框。（我猜可能需要第二个循环？也许我应该遍历 df 名称列表？）
The output would be df1...dfn
输出将是 df1...dfn
回答by Peter Leimbigler
EDIT: I initially misread your question, and thought you wanted to concatenate all the DataFrames into one. This does that:
编辑：我最初误读了您的问题，并认为您想将所有 DataFrame 连接成一个。这是这样做的：
dfx = pd.concat([df for df in analysisdict.values()], ignore_index=True)
(Thanks to @paul-h for the ignore_index=Truetip)
（感谢@paul-h 的ignore_index=True提示）
I read your question more carefully and realized that you're asking how to assign each DataFrame in your dictionary to its ownvariable, resulting in separate DataFrames named df1, df2, ..., dfn. Everything in my experience says that dynamically creating variables in this way is an anti-pattern, and best left to dictionaries. Check out the discussion here: How can you dynamically create variables via a while loop?
我更仔细地阅读了您的问题，并意识到您在询问如何将字典中的每个 DataFrame 分配给它自己的变量，从而生成名为df1, df2, ..., dfn. 我的经验表明，以这种方式动态创建变量是一种反模式，最好留给字典。查看此处的讨论：如何通过 while 循环动态创建变量？
