C语言 C:警告:数组初始值设定项中的元素过多;'xxx' 即将初始化;需要“char *”,但类型为“int”

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时间:2020-09-02 04:33:19  来源:igfitidea点击:

C: warning: excess elements in array initializer; near initialization for ‘xxx' ; expects ‘char *’, but has type ‘int’

carrayscharinitializer

提问by wojteo

I've some warnings while trying to compile program in C language:

我在尝试用 C 语言编译程序时有一些警告:

13:20: warning: excess elements in array initializer [enabled by default]

13:20: warning: (near initialization for ‘litera') [enabled by default]

22:18: warning: excess elements in array initializer [enabled by default]

22:18: warning: (near initialization for ‘liczba') [enabled by default]

43:1: warning: format ‘%s' expects argument of type ‘char *', but argument 2 has type ‘int' [-Wformat]

45:2: warning: format ‘%s' expects argument of type ‘char *', but argument 2 has type ‘int' [-Wformat]

55:2: warning: format ‘%s' expects argument of type ‘char *', but argument 2 has type ‘int' [-Wformat]
13:20: warning: excess elements in array initializer [enabled by default]

13:20: warning: (near initialization for ‘litera') [enabled by default]

22:18: warning: excess elements in array initializer [enabled by default]

22:18: warning: (near initialization for ‘liczba') [enabled by default]

43:1: warning: format ‘%s' expects argument of type ‘char *', but argument 2 has type ‘int' [-Wformat]

45:2: warning: format ‘%s' expects argument of type ‘char *', but argument 2 has type ‘int' [-Wformat]

55:2: warning: format ‘%s' expects argument of type ‘char *', but argument 2 has type ‘int' [-Wformat]

The source is:

来源是:

char litera[63] = {'E', 'G', 'H', 'F', 'E', 'G', 'H', 'F',
                   'D', 'B', 'A', 'C', 'D', 'B', 'A', 'C', 
                   'B', 'A', 'C', 'D', 'C', 'A', 'B', 'D', 
                   'F', 'H', 'G', 'E', 'F', 'H', 'G', 'E', 
                   'C', 'D', 'B', 'A', 'B', 'A', 'C', 'D', 
                   'F', 'E', 'G', 'H', 'G', 'H', 'F', 'G', 
                   'H', 'F', 'E', 'F', 'H', 'G', 'E', 'C',
    /*line13:*/    'A', 'B', 'D', 'C', 'A', 'B', 'D', 'E'};

int liczba[63] ={'8', '7', '5', '6', '4', '3', '1', '2', 
                 '1', '2', '4', '3', '5', '6', '8', '7', 
                 '5', '7', '8', '6', '4', '3', '1', '2', 
                 '1', '2', '4', '3', '5', '6', '8', '7', 
                 '6', '8', '7', '5', '3', '1', '2', '4', 
                 '3', '1', '2', '4', '6', '8', '7', '5', 
                 '7', '8', '6', '4', '3', '1', '2', '1', 
    /*line22*/   '2', '4', '3', '5', '6', '8', '7', '5'};


int i=0, x=0, n;
char a;
int b=0;
printf("Podaj liter? z pola startowego skoczka(du?e litery)\n");
scanf("%s", &a);
printf("Podaj liczb? z pola startowego skoczka \n");
scanf("%d", &b);

if (b<=0 || b>8){
    printf("Z?a pozycja skoczka\n");
    return 0;
    }

while (litera[i] != a || liczba[i] != b){
    ++i;
    }
n=i;

/*line43*/ printf("Trasa skoczka od punktu %s %d to:\n", a, b); 
while (i<=64){
/*line45*/ printf("%s%d ", litera[i], liczba[i]);
    ++i;

    ++x;
    x=x%8;
    if(x==0)
        printf("/n");
    }
i=0;
while (i<n){
/*line55*/ printf("%s%d ", litera[i], liczba[i]);

    ++i;

    ++x;
    x=x%8;
    if(x==0)
        printf("/n");
    }

also I have "core dumped" after scanf("%d", &b);, but int b=0;doesn't make a problem...

之后我也有“核心转储” scanf("%d", &b);,但int b=0;没有问题......

回答by raina77ow

Two errors here: first, you're trying to declare arrays[63]for storing 64 elements, as you've probably confused the size of array (n) with the maximum possible index value (that's n - 1). So it definitely should be litera[64]and liczba[64]. BTW, you have to change this line too - while (i<=64): otherwise you end up trying to access 65thelement.

这里有两个错误:首先,您试图声明arrays[63]存储 64 个元素,因为您可能将数组 ( n)的大小与最大可能的索引值(即n - 1)混淆了。所以它绝对应该是litera[64]and liczba[64]。顺便说一句,您也必须更改此行 - while (i<=64):否则您最终会尝试访问第 65 个元素。

And second, you're trying to fill charvalue with %sformat specifier for scanf, while you should have used %chere.

其次,您尝试char使用%sscanf 的格式说明符填充值,而您应该在%c这里使用。

Also, can't help wondering why you declare liczbaarray as one that stores ints, that initialize it with array of chars. All these '1', '2', etc... literals represent NOT the corresponding digits - but the charcodes for them. I doubt that was your intent.

此外,不禁想知道为什么将liczba数组声明为存储ints 的数组,并使用chars数组对其进行初始化。所有这些“1”、“2”等……文字代表的不是相应的数字——而是它们的字符代码。我怀疑那是你的意图。

回答by Nazim

char litera[63] -> char litera[64] int liczba[63] -> int liczba[64]

字符字面量[63] -> 字符字面量[64] int liczba[63] -> int liczba[64]

make 64 in the place of array size initialization . initialize 1 more index when you are initializing the size of array.

用 64 代替数组大小初始化。初始化数组大小时,再初始化 1 个索引。