jQuery 如何检查字母数字字符
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How to check for alphanumeric characters
提问by AKor
I'm writing a custom method for a jQuery plugin:
我正在为 jQuery 插件编写自定义方法：
jQuery.validator.addMethod("alphanumeric", function(value, element) {
return this.optional(element) || (/*contains "^[a-zA-Z0-9]*$"*/);
});
I know the regexp for what I want, but I'm not sure how to write something in JS that will evaluate to True if it contains the alphanumeric characters. Any help?
我知道我想要什么的正则表达式，但我不确定如何在 JS 中编写一些东西，如果它包含字母数字字符，它将评估为 True。有什么帮助吗？
回答by Josiah Ruddell
回答by Pablo Hernández - OtakuPahp
If you want to use Spanish chars in your alphanumeric validation you can use this:
如果你想在你的字母数字验证中使用西班牙语字符，你可以使用这个：
jQuery.validator.addMethod("alphanumeric", function(value, element) {
return this.optional(element) || /^[a-zA-Z0-9áéíóúáéíóú?? ]+$/.test(value);
});
I also added a blank space to let users add words
我还添加了一个空格让用户添加单词
回答by Cfreak
You can use regexes in JavaScript:
您可以在 JavaScript 中使用正则表达式：
if( yourstring.match(/^[a-zA-Z0-9]+/) ) {
return true
}
Note that I used +instead of *. With *it would return true if the string was empty
请注意，我使用了+而不是*. 随着*它会返回true，如果该字符串是空的
回答by Parvez
// use below ... It is better parvez abobjects.com
jQuery.validator.addMethod("postalcode", function(postalcode, element) {
if( this.optional(element) || /^[a-zA-Z\u00C0-\u00ff]+$/.test(postalcode)){
return false;
}else{
return this.optional(element) || /^[a-zA-Z0-9]+/.test(postalcode);
}
}, "<br>Invalid zip code");
rules:{
ccZip:{
postalcode : true
},
phone:{required: true},
This will validate zip code having no letters but alphanumeric
回答by Eric Frick
$("input:text").filter(function() {
return this.value.match(/^[a-zA-Z0-9]+/);
})
