php 警告:explode() 期望参数 2 是字符串,给定数组

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时间:2020-08-25 22:51:22  来源:igfitidea点击:

Warning: explode() expects parameter 2 to be string, array given

phparraysexplode

提问by ftxn

The Script:

剧本:

<?php

    $tqs = "SELECT * FROM `table_two`";
    $tqr = mysqli_query($dbc, $tqs);
    $row = mysqli_fetch_assoc($tqr);
    $thearray[] = $row['some_text_id'];

    // Prints e.g.: Array ( [0] => 164, 165, 166 )
    print_r($thearray);

    echo "<br/><br/>";
    echo "<br/><br/>";

    $thearray = explode(", ", $thearray);
    print_r($thearray);

?>

I have the following entry in one row of the column "some_text_id":

我在“some_text_id”列的一行中有以下条目:

164, 165, 166

I am looking to "explode" this by the comma and have it stored in an array, so I can select the numbers individually, e.g.:

我希望通过逗号“分解”它并将其存储在数组中,因此我可以单独选择数字,例如:

myarray[0], myarray[1], myarray[2]

Though I am getting the following error message:

虽然我收到以下错误消息:

Warning: explode() expects parameter 2 to be string, array given in ... (points to the explode function)

警告:explode() 期望参数 2 是字符串,数组在 ...(指向爆炸函数)

Any suggestions on how to do this?

关于如何做到这一点的任何建议?

回答by John Conde

Skip the part where you put the database results into an array. It's completely unnecessary:

跳过将数据库结果放入数组的部分。完全没有必要:

<?php

    $tqs = "SELECT * FROM `table_two`";
    $tqr = mysqli_query($dbc, $tqs);
    $row = mysqli_fetch_assoc($tqr);

    // Prints e.g.: 164, 165, 166
    print_r($row['some_text_id']);

    echo "<br/><br/>";
    echo "<br/><br/>";

    $thearray = explode(", ", $row['some_text_id']);
    print_r($thearray);

?>