C语言 如何从 ASCII 转换为十六进制，反之亦然？
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How to convert from ASCII to Hex and vice versa?
提问by kiran
I need to convert ASCIIto HEXand HEXto ASCIIby using a C program.
How can I do that?
我需要转换ASCII到HEX并HEX以ASCII通过使用一个C程序。
我怎样才能做到这一点？
回答by Eddie Sullivan
Here's a simplistic function to convert one character to a hexadecimal string.
这是将一个字符转换为十六进制字符串的简单函数。
char hexDigit(unsigned n)
{
if (n < 10) {
return n + '0';
} else {
return (n - 10) + 'A';
}
}
void charToHex(char c, char hex[3])
{
hex[0] = hexDigit(c / 0x10);
hex[1] = hexDigit(c % 0x10);
hex[2] = '##代码##';
}
回答by Goz
Its pretty easy. Scan through character by character ... best to start from the end. If the character is a number between 0 and 9 or a letter between a and f then place it in the correct position by left shifting it by the number of digits you've found so far.
它很容易。逐个字符扫描...最好从结尾开始。如果字符是 0 到 9 之间的数字或 a 和 f 之间的字母，则将其左移到目前为止找到的数字位数，从而将其放置在正确的位置。
For converting to a string then you do similar but first you mask and right shift the values. You then convert them to the character and place them in the string.
为了转换为字符串，您可以执行类似的操作，但首先要屏蔽并右移值。然后将它们转换为字符并将它们放入字符串中。
