元组函数的 Scala 返回类型
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Scala return type for tuple-functions
提问by Felix
I want to make a scala function which returns a scala tuple.
我想创建一个返回 scala 元组的 scala 函数。
I can do a function like this:
我可以做这样的功能：
def foo = (1,"hello","world")
and this will work fine, but now I want to tell the compiler what I expect to be returned from the function instead of using the built in type inference (after all, I have no idea what a (1,"hello","world")is).
这将工作正常，但现在我想告诉编译器我期望从函数返回什么，而不是使用内置类型推断（毕竟，我不知道 a(1,"hello","world")是什么）。
回答by oxbow_lakes
def foo : (Int, String, String) = (1, "Hello", "World")
The compiler will interpret the type (Int, String, String)as a Tuple3[Int, String, String]
编译器会将类型解释(Int, String, String)为Tuple3[Int, String, String]
回答by WillD
Also, you can create a type alias if you get tired of writing (Int,String,String)
此外，如果您厌倦了编写 (Int,String,String)，可以创建类型别名
type HelloWorld = (Int,String,String)
...
def foo : HelloWorld = (1, "Hello", "World")
/// and even this is you want to make it more OOish
def bar : HelloWorld = HelloWorld(1, "Hello", "World")
