Linux 我如何递归地grep？
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How do I grep recursively?
提问by wpiri
How do I recursively grepall directories and subdirectories?
如何递归grep所有目录和子目录？
find . | xargs grep "texthere" *
采纳答案by Vinko Vrsalovic
grep -r "texthere" .
The first parameter represents the regular expression to search for, while the second one represents the directory that should be searched. In this case, .means the current directory.
第一个参数表示要搜索的正则表达式，而第二个参数表示应该搜索的目录。在这种情况下，.表示当前目录。
Note: This works for GNU grep, and on some platforms like Solaris you must specifically use GNU grep as opposed to legacy implementation. For Solaris this is the ggrepcommand.
注意：这适用于 GNU grep，并且在某些平台（如 Solaris）上，您必须专门使用 GNU grep，而不是传统实现。对于 Solaris，这是ggrep命令。
回答by Kurt
Also:
还：
find ./ -type f -print0 | xargs -0 grep "foo"
but grep -ris a better answer.
但是grep -r一个更好的答案。
回答by christangrant
If you know the extension or pattern of the file you would like, another method is to use --includeoption:
如果您知道所需文件的扩展名或模式，另一种方法是使用--include选项：
grep -r --include "*.txt" texthere .
You can also mention files to exclude with --exclude.
您还可以提及要排除的文件--exclude。
Ag
银
If you frequently search through code, Ag (The Silver Searcher)is a much faster alternative to grep, that's customized for searching code. For instance, it's recursive by default and automatically ignores files and directories listed in .gitignore, so you don't have to keep passing the same cumbersome exclude options to grep or find.
如果您经常搜索代码，Ag（The Silver Searcher）是 grep 的更快替代品，它是为搜索代码而定制的。例如，默认情况下它是递归的，并自动忽略 中列出的文件和目录.gitignore，因此您不必一直将相同的繁琐排除选项传递给 grep 或 find。
回答by chim
just the filenames can be useful too
只是文件名也很有用
grep -r -l "foo" .
回答by VonC
I now always use (even on Windows with GoW -- Gnu on Windows):
我现在总是使用（即使在带有GoW 的Windows 上-Windows 上的Gnu）：
grep --include="*.xxx" -nRHI "my Text to grep" *
That includes the following options:
这包括以下选项：
--include=PATTERN
Recurse in directories only searching file matching
PATTERN.
在目录中递归只搜索匹配的文件
PATTERN。
-n, --line-number
Prefix each line of output with the line number within its input file.
使用输入文件中的行号为每一行输出添加前缀。
(Note: phuclvadds in the commentsthat -ndecreases performance a lot so, so you might want to skip that option)
（注：phuclv加在评论这 -n会降低性能了很多，所以，所以你可能想跳过该选项）
-R, -r, --recursive
Read all files under each directory, recursively; this is equivalent to the
-d recurseoption.
递归读取每个目录下的所有文件；这相当于
-d recurse选项。
-H, --with-filename
Print the filename for each match.
打印每个匹配项的文件名。
-I
Process a binary file as if it did not contain matching data;
this is equivalent to the--binary-files=without-matchoption.
处理一个二进制文件，就好像它不包含匹配的数据一样；
这相当于--binary-files=without-match选项。
And I can add 'i' (-nRHIi), if I want case-insensitive results.
如果我想要不区分大小写的结果，我可以添加 ' i' ( -nRHIi)。
I can get:
我可以得到：
/home/vonc/gitpoc/passenger/gitlist/github #grep --include="*.php" -nRHI "hidden" *
src/GitList/Application.php:43: 'git.hidden' => $config->get('git', 'hidden') ? $config->get('git', 'hidden') : array(),
src/GitList/Provider/GitServiceProvider.php:21: $options['hidden'] = $app['git.hidden'];
tests/InterfaceTest.php:32: $options['hidden'] = array(self::$tmpdir . '/hiddenrepo');
vendor/klaussilveira/gitter/lib/Gitter/Client.php:20: protected $hidden;
vendor/klaussilveira/gitter/lib/Gitter/Client.php:170: * Get hidden repository list
vendor/klaussilveira/gitter/lib/Gitter/Client.php:176: return $this->hidden;
...
回答by rook
In POSIX systems, you don't find -rparameter for grepand your grep -rn "stuff" .won't run, but if you use findcommand it will:
在POSIX系统中，你找不到-r的参数grep和你grep -rn "stuff" .将无法运行，但如果你使用find命令将：
find . -type f -exec grep -n "stuff" {} \; -print
find . -type f -exec grep -n "stuff" {} \; -print
Agreed by Solarisand HP-UX.
Solaris和同意HP-UX。
回答by sumit kumar
This should work:
这应该有效：
grep -R "texthere" *
回答by m.thome
Note that find . -type f | xargs grep whateversorts of solutions will run into "Argument list to long" errors when there are too many files matched by find.
请注意，find . -type f | xargs grep whatever当 find 匹配的文件太多时，各种解决方案将遇到“参数列表长”错误。
The best bet is grep -rbut if that isn't available, use find . -type f -exec grep -H whatever {} \;instead.
最好的办法是，grep -r但如果那不可用，请find . -type f -exec grep -H whatever {} \;改用。
回答by dranxo
ag is my favorite way to do this now github.com/ggreer/the_silver_searcher. It's basically the same thing as ack but with a few more optimizations.
ag 是我现在最喜欢的方式github.com/ggreer/the_silver_searcher。它与 ack 基本相同，但还有一些优化。
Here's a short benchmark. I clear the cache before each test (cf https://askubuntu.com/questions/155768/how-do-i-clean-or-disable-the-memory-cache)
这是一个简短的基准。我在每次测试之前清除缓存（参见https://askubuntu.com/questions/155768/how-do-i-clean-or-disable-the-memory-cache）
ryan@3G08$ sync && echo 3 | sudo tee /proc/sys/vm/drop_caches
3
ryan@3G08$ time grep -r "hey ya" .
real 0m9.458s
user 0m0.368s
sys 0m3.788s
ryan@3G08:$ sync && echo 3 | sudo tee /proc/sys/vm/drop_caches
3
ryan@3G08$ time ack-grep "hey ya" .
real 0m6.296s
user 0m0.716s
sys 0m1.056s
ryan@3G08$ sync && echo 3 | sudo tee /proc/sys/vm/drop_caches
3
ryan@3G08$ time ag "hey ya" .
real 0m5.641s
user 0m0.356s
sys 0m3.444s
ryan@3G08$ time ag "hey ya" . #test without first clearing cache
real 0m0.154s
user 0m0.224s
sys 0m0.172s
回答by user3606336
In my IBM AIX Server (OS version: AIX 5.2), use:
在我的 IBM AIX 服务器（操作系统版本：AIX 5.2）中，使用：
find ./ -type f -print -exec grep -n -i "stringYouWannaFind" {} \;
this will print out path/file name and relative line number in the file like:
这将打印出文件中的路径/文件名和相对行号，例如：
./inc/xxxx_x.h
./inc/xxxx_x.h
2865: /** Description : stringYouWannaFind */
2865：/** 描述：stringYouWannaFind */
anyway,it works for me : )
无论如何，它对我有用:)
