php Laravel 在今天之前统治...怎么办
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Laravel before today rule... how to do
提问by Phil
For this rule I am getting an error syntax error, unexpected '.', expecting ')'
对于这条规则，我收到一个错误 syntax error, unexpected '.', expecting ')'
public static $rules = array(
'first_name' => 'required|alpha-dash',
'last_name' => ' required|alpha-dash',
'media_release' => 'required|boolean',
'birthday' => 'before:' . date('Y-m-d')
);
I can't figure out why this won't work. I'm running Laravel 4.2.12
我不明白为什么这行不通。我正在运行 Laravel 4.2.12
采纳答案by mopo922
You can't use a function when defining class member variables. You'll have to move that part to your constructor:
定义类成员变量时不能使用函数。您必须将该部分移至构造函数：
<?php
class Foo {
public static $rules = array(
'first_name' => 'required|alpha-dash',
'last_name' => ' required|alpha-dash',
'media_release' => 'required|boolean'
);
public function __construct()
{
self::$rules['birthday'] = 'before:' . date('Y-m-d');
}
EDIT:
编辑：
The above solution may not work in Laravel. You may have to use a "Custom Validator" instead:
上述解决方案在 Laravel 中可能不起作用。您可能必须改用“自定义验证器”：
http://laravel.com/docs/4.2/validation#custom-validation-rules
http://laravel.com/docs/4.2/validation#custom-validation-rules
UPDATE:
更新：
Looks like Laravel 5 introduced a better solution. See the answer by Fernando, below.
看起来 Laravel 5 引入了更好的解决方案。请参阅下面 Fernando 的回答。
回答by Fernando lugo
try this:
尝试这个：
'birthday' => 'date_format:Y-m-d|before:today',
bye
再见
回答by lmarcelocc
Just for future users:
仅供未来用户使用：
Laravel 5 using form requests:
Laravel 5 使用表单请求：
'birthday' => 'before:today', // Doesn't accept today date
'birthday' => 'before:tomorrow', // Accept today date
回答by António Almeida
I recommend you to add a beforeand an afterstatement for birthdays.
我建议你为生日添加一个before和一个after声明。
'birthday' => date_format:Y-m-d|before:today|after:1900-01-01
You'll avoid entries like 1111-1-1because no one alive was born before the year 1900.
您将避免出现像1111-1-1因为 1900 年之前没有人出生这样的条目。
