如果变量等于值 php
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If variable equals value php
提问by llw
I am trying to do a check before the data inserts into the MySQL query. Here is the code;
我正在尝试在数据插入 MySQL 查询之前进行检查。这是代码；
$userid = ($vbulletin->userinfo['userid']);
$sql3 = mysql_query("SELECT * FROM table WHERE ID='$_POST[hiddenID]'");
while ($row = mysql_fetch_array($sql3)){
$toon = $row['toonname'];
$laff = $row['tlaff'];
$type = $row['ttype'];
if ($type == 1){
$type == "Bear";
} elseif ($type == 2){
$type == "Cat";
} elseif ($type == 3){
$type == "Dog";
}
}
However, this isn't working. Basically, there are different values in the 'table' for each type. 1 means Bear, 2 means Cat, and 3 means Dog.
但是，这不起作用。基本上，每种类型的“表”中有不同的值。1代表熊，2代表猫，3代表狗。
Thanks to whomever can help see a problem in my script!
感谢任何可以帮助查看我的脚本中的问题的人！
回答by Jezen Thomas
You are comparing, not assigning:
您是在比较，而不是分配：
if ($type == 1){
$type = "Bear";
}
You compare values with ==or ===.
您将值与==或进行比较===。
You assign values with =.
您使用 分配值=。
You could write less code to achieve the same result too, with a switchstatement, or just a bunch of ifs without the elseifs.
您也可以编写更少的代码来实现相同的结果switch，只需使用一条语句，或者只是一堆ifs 而没有elseifs。
if ($type == 1) $type = "Bear";
if ($type == 2) $type = "Cat";
if ($type == 3) $type = "Dog";
I would make a function for it, like this:
我会为它做一个函数，像这样：
function get_species($type) {
switch ($type):
case 1: return 'Bear';
case 2: return 'Cat';
case 3: return 'Dog';
default: return 'Jeff Atwood';
endswitch;
}
$type = get_species($row['ttype']);
回答by PurkkaKoodari
You are using ==instead of =. It compares the variable to the new value. Use =to set the value.
您正在使用==而不是=. 它将变量与新值进行比较。使用=设定值。
if ($type == 1){
$type = "Bear";
} elseif ($type == 2){
$type = "Cat";
} elseif ($type == 3){
$type = "Dog";
}
回答by LeonardChallis
You're using ==to assign values:
您正在使用==分配值：
$type == bear;
$type == bear;
Should be:
应该：
$type = bear;
$type = bear;
回答by Porta Shqipe
if ($type == 1) {$displayVar = "Bear";}
Example:
例子：
<form method="post" action="results.php">
How many horns does a unicorn have? <br />
<input type="text" name="inputField" id="inputField" /> <br />
<input type="submit" value="Submit" /> <br />
</form>
Results:
结果：
<?php
$inputVar = $_POST["inputField"];
if ($inputVar == 1) {$answerVar = "correct";}
else $answerVar = "<strong>not correct</strong>";
?>
<?php
echo "Your answer is " . $answerVar . "<br />";
?>
