将 PHP 日期转换为 javascript 日期格式
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Convert PHP date into javascript date format
提问by LeeTee
I have a PHP script that outputs an array of data. This is then transformed into JSONusing the json_encode()function.
我有一个输出数据数组的 PHP 脚本。然后将其转换为JSON使用该json_encode()函数。
My issue is I have a date within my array and it's not in the correct JavaScript format. How can I convert this within PHP so it is?
我的问题是我的数组中有一个日期，但它的 JavaScript 格式不正确。我怎样才能在 PHP 中转换它呢？
$newticket['ThreadID'] = $addticket;
$newticket['Subject'] = $subject;
//$newticket['DateCreated'] = date('d-m-Y G:H');
Instead of the above for the date I need the equivalent of the JavaScript function
而不是上面的日期，我需要等效的 JavaScript 函数
new Date()
新日期()
When I output the above I get the following "Fri Jun 01 2012 11:08:48 GMT+0100 (GMT Daylight Time)" However, If I format my PHP date to be the same, then JavaScript rejects it. Confused...
当我输出上述内容时，我得到以下信息“Fri Jun 01 2012 11:08:48 GMT+0100（GMT Daylight Time）”但是，如果我将 PHP 日期格式设置为相同，则 JavaScript 会拒绝它。使困惑...
Can anyone help?
任何人都可以帮忙吗？
回答by jeremyharris
You should probably just use a timestamp
您可能应该只使用时间戳
$newticket['DateCreated'] = strtotime('now');
Then convert it to a Javascript date
然后将其转换为 Javascript 日期
// make sure to convert from unix timestamp
var now = new Date(dateFromPHP * 1000);
回答by Javlonbek
Javascript Date class supports ISO 8601 date format so I would recommend:
Javascript Date 类支持 ISO 8601 日期格式，所以我建议：
<?php
date('c', $yourDateTime);
// or for objects
$dateTimeObject->format('c');
?>
documentation says that:
format character 'c' is ISO 8601 date (added in PHP 5)
example: 2004-02-12T15:19:21+00:00
文档说：格式字符 'c' 是 ISO 8601 日期（在 PHP 5 中添加）
示例：2004-02-12T15:19:21+00:00
for more information: http://php.net/manual/en/function.date.php
回答by Rahul Gupta
It is pretty simple.
这很简单。
PHP code:
PHP代码：
$formatted_date = $newticket['DateCreated'] = date('Y/m/d H:i:s');
Javascript code:
Javascript代码：
var javascript_date = new Date("<?php echo $formatted_date; ?>");
回答by Tiago Buzatto
Is very simple, I'm use this:
很简单，我用这个：
new Date("<?= date('Y/m/d H:i:s'); ?>");
回答by xarlymg89
An improvement or simplification of @jeremyharris answer would be this one:
@jeremyharris 答案的改进或简化是这样的：
DateTime objects in PHP have the getTimestamp()format, use it and multiply the value by 1000:
PHP 中的 DateTime 对象具有getTimestamp()格式，使用它并将值乘以 1000：
<?php
$phpDateTimeStamp = new Date('Y/m/d H:i:s')->getTimestamp() * 1000;
?>
// JavaScript
let startTime = new Date(phpDateTimeStamp);
回答by Scott Saunders
$newticket['DateCreated'] = date('d-m-Y G:H', strtotime($phpDateVariable));
回答by Joan-Diego Rodriguez
If you want to be more precise with your timestamp, you should use microtime() instead of now().
如果您想更精确地使用时间戳，您应该使用 microtime() 而不是 now()。
That gives you:
这给你：
echo round(microtime(TRUE)*1000);
For a milisecond, javascript-like timestamp in php.
一毫秒，php 中类似 javascript 的时间戳。
