javascript 茉莉花间谍嵌套对象
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/17120921/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
jasmine spy on nested object
提问by Amitava
My service object looks like this:
我的服务对象如下所示：
var appService = {
serviceOne: {
get: function(){}
},
serviceTwo: {
query: function(){}
}
}
I would like to mock appService,something like:
我想模拟 appService，例如：
expect(appService.serviceTwo.query).toHaveBeenCalled();
How would I go about doing it?
我将如何去做？
回答by Amitava
OK I got this working with this:
好的，我得到了这个：
appService: {
serviceOne: jasmine.createSpyObj('serviceOne', ['get']),
serviceTwo: jasmine.createSpyObj('serviceTwo', ['query'])
}
I hope it is the right way to do.
我希望这是正确的做法。
回答by Andreas K?berle
Just replace the function with jasmine spies:
只需用 jasmine spies 替换该函数：
var appService = {
serviceOne: {
get: jasmine.createSpy()
},
serviceTwo: {
query: jasmine.createSpy()
}
}
later on:
稍后的：
expect(appService.serviceTwo.query).toHaveBeenCalled()
回答by Efonzie
I ran into a very similar problem and got a solution to work that allows spying at multiple levels relatively easily.
我遇到了一个非常相似的问题，并找到了一个可以相对轻松地在多个级别进行间谍活动的解决方案。
appService = {
serviceOne: jasmine.createSpy().and.returnValue({
get: jasmine.createSpy()
},
serviceTwo: jasmine.createSpy().and.returnValue({
query: jasmine.createSpy()
}
}
This solution allows the following code to be called in a unit test
此解决方案允许在单元测试中调用以下代码
expect(appService.serviceOne).toHaveBeenCalledWith('foobar');
expect(appService.serviceOne().get).toHaveBeenCalledWith('some', 'params');
Note: this code has not been tested; however, I have a very simmilar implementation in one of my apps. Hope this helps!
注：此代码未经测试；但是，我在我的一个应用程序中有一个非常相似的实现。希望这可以帮助！
回答by Adam
The examples above show explicit, named spy creation. However, one can simply continue chaining in the jasmine.spyOnfunction to get to the method level.
上面的示例显示了显式的命名间谍创建。但是，您可以简单地在jasmine.spyOn函数中继续链接以到达方法级别。
For a deeply nested object:
对于深度嵌套的对象：
var appService = {
serviceOne: {
get: function(){}
}
};
jasmine.spyOn(appService.serviceOne, 'get');
expect(appService.serviceOne.get).toHaveBeenCalled();
