如何从控制器类打开 JavaFX FileChooser?

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时间:2020-08-11 00:30:06  来源:igfitidea点击:

How do I open the JavaFX FileChooser from a controller class?

javajavafxfilechooser

提问by Electric Coffee

My problem is that all the examples of using FileChooserrequires you to pass in a stage. Only problem is that my UI is defined in an fxmlfile, which uses a controller class separate from the main stage.

我的问题是所有使用的例子都FileChooser需要你通过一个阶段。唯一的问题是我的 UI 是在一个fxml文件中定义的,该文件使用与主阶段分开的控制器类。

@FXML protected void locateFile(ActionEvent event) {
    FileChooser chooser = new FileChooser();
    chooser.setTitle("Open File");
    chooser.showOpenDialog(???);
}

What do I put at the ???to make it work? Like I said, I don't have any references to any stages in the controller class, so what do I do?

我在里面放了什么才能???让它工作?就像我说的,我没有对控制器类中的任何阶段进行任何引用,那我该怎么办?

采纳答案by James_D

For any node in your scene (for example, the root node; but any node you have injected with @FXMLwill do), do

对于场景中的任何节点(例如,根节点;但您注入的任何节点都@FXML可以),请执行

chooser.showOpenDialog(node.getScene().getWindow());

回答by Mansueli

You don't have to stick with the Stage created in the Application you can either:

您不必坚持使用在应用程序中创建的舞台,您可以:

@FXML protected void locateFile(ActionEvent event) {
    FileChooser chooser = new FileChooser();
    chooser.setTitle("Open File");
    File file = chooser.showOpenDialog(new Stage());
}

Or if you want to keep using the same stage then you have to pass the stage to the controller before:

或者,如果您想继续使用同一个舞台,那么您必须先将舞台传递给控制器​​:

    FXMLLoader loader = new FXMLLoader(getClass().getResource("yourFXMLDocument.fxml"));
    Parent root = (Parent)loader.load();
    MyController myController = loader.getController();
    myController.setStage(stage);

and you will have the main stage of the Application there to be used as you please.

您将可以随意使用应用程序的主要阶段。

回答by spinnaker15136

From a menu item

从菜单项

public class SerialDecoderController implements Initializable {

  @FXML
  private MenuItem fileOpen;

  @Override
  public void initialize(URL url, ResourceBundle rb) {
    // TODO
 }    


public void fileOpen (ActionEvent event) {

    FileChooser fileChooser = new FileChooser();
    fileChooser.setTitle("Open Resource File"); 
    fileChooser.showOpenDialog(fileOpen.getParentPopup().getScene().getWindow());

}

回答by luke8800gts

Alternatively, what worked for me: simply put null.

或者,对我有用的是:简单地将null.

@FXML
private void onClick(ActionEvent event) {
    File file = fileChooser.showOpenDialog(null);
    if (file != null) {
       //TODO
    }
}