javascript WebRTC 无法添加 ICE 候选

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/25355913/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-10-28 04:25:00  来源:igfitidea点击:

WebRTC The ICE candidate could not be added

javascriptwebrtc

提问by yang Joe

I am trying to establish a p2p audio/video connection b/w two peers. Following: Getting started with WebRTC.

我正在尝试建立 b/w 两个对等点的 p2p 音频/视频连接。如下:WebRTC 入门

It works fine at my home in LAN Environment between 2 PCs, but throws an error message when running at my company's LAN Environment, there is part the javascript

它在我家的 2 台 PC 之间的 LAN 环境中运行良好,但是在我公司的 LAN 环境中运行时会抛出错误消息,部分是 javascript

function processSignalingMessage(message) {
        var msg = JSON.parse(message);

        if (msg.type === 'offer') {
            // Callee creates PeerConnection
            if (!initiator && !started)
                maybeStart();

            // We only know JSEP version after createPeerConnection().
            if (isRTCPeerConnection)
                pc.setRemoteDescription(new RTCSessionDescription(msg));
            else
                pc.setRemoteDescription(pc.SDP_OFFER,
                        new SessionDescription(msg.sdp));

            doAnswer();
        } else if (msg.type === 'answer' && started) {
            pc.setRemoteDescription(new RTCSessionDescription(msg));
        } else if (msg.type === 'candidate' && started) {
            var candidate = new RTCIceCandidate({
                sdpMLineIndex : msg.label,
                candidate : msg.candidate
            });
            pc.addIceCandidate(candidate);
        } else if (msg.type === 'bye' && started) {
            onRemoteHangup();
        }
    }

when the first user recieved message "type":"candidate",get wrong

当第一个用户收到消息“type”:“candidate”时,出错

and part of the console log:

和控制台日志的一部分:

  • Creating PeerConnection
  • Created webkitRTCPeerConnnection with config "{"iceServers":[{"url":"stun:stun.l.google.com:19302"}]}"
  • Adding local stream
  • Sending answer to peer
  • recieved message : {"type":"candidate","label":0,"id":"audio","candidate":"a=candidate:1613033416 1 udp 2113937151 192.168.1.233 56946 typ host generation 0\r\n"}
  • Uncaught SyntaxError: Failed to execute 'addIceCandidate' on 'RTCPeerConnection': The ICE candidate could not be added
  • recieved message : {"type":"candidat".......}
  • Uncaught SyntaxError: Failed to execute 'addIceCandidate' on 'RTCPeerConnection': The ICE candidate could not be added
  • recieved message : {"type":"candidat".......}
  • Uncaught SyntaxError: Failed to execute 'addIceCandidate' on 'RTCPeerConnection': The ICE candidate could not be added
  • 创建对等连接
  • 使用配置 "{"iceServers":[{"url":"stun:stun.l.google.com:19302"}]}" 创建了 webkitRTCPeerConnnection
  • 添加本地流
  • 将答案发送给对等方
  • 收到消息:{"type":"candidate","label":0,"id":"audio","candidate":"a=candidate:1613033416 1 udp 2113937151 192.168.1.233 56946 typ\host generation n"}
  • 未捕获的语法错误:无法在“RTCPeerConnection”上执行“addIceCandidate”:无法添加 ICE 候选
  • 收到消息:{"type":"candidat".......}
  • 未捕获的语法错误:无法在“RTCPeerConnection”上执行“addIceCandidate”:无法添加 ICE 候选
  • 收到消息:{"type":"candidat".......}
  • 未捕获的语法错误:无法在“RTCPeerConnection”上执行“addIceCandidate”:无法添加 ICE 候选

回答by wontonsoup

I think you can create the ICE candidate message by using just the msg.candidate,

我认为您可以仅使用 msg.candidate 来创建 ICE 候选消息,

var candidate = new RTCIceCandidate(msg.candidate);

And pass that into the addIceCandidatefunction

并将其传递给addIceCandidate函数