laravel 如何在laravel中更改请求参数的值
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How to change value of a request parameter in laravel
提问by Morteza Negahi
I need to change value of my request parameter like this:
我需要像这样更改我的请求参数的值：
$request->name = "My Value!";
I use this code but does not work:
我使用此代码但不起作用：
$request->offsetSet('img', $img);
回答by Alexey Mezenin
Try to:
尝试：
$requestData = $request->all();
$requestData['img'] = $img;
Another way to do it:
另一种方法：
$request->merge(['img' => $img]);
Thanks to @JoelHinz for this.
感谢@JoelHinz 为此。
If you want to add or overwrite nested data:
如果要添加或覆盖嵌套数据：
$data['some']['thing'] = 'value';
$request->merge($data);
If you do not inject Request $requestobject, you can use the global request()helper or \Request::facade instead of $request
如果不注入Request $request对象，则可以使用全局request()助手或\Request::外观代替$request
回答by doncadavona
Use merge():
使用merge()：
$request->merge([
'user_id' => $modified_user_id_here,
]);
Simple! No need to transfer the entire $request->all()to another variable.
简单的！无需将整个转移$request->all()到另一个变量。
回答by Alaa Moneam
If you need to customize the request
如果您需要自定义请求
$data = $request->all();
you can pass the name of the field and the value
您可以传递字段的名称和值
$data['product_ref_code'] = 1650;
and finally pass the new request
最后通过新的请求
$last = Product::create($data);
回答by Phuc
It work for me
它对我有用
$request = new Request();
$request->headers->set('content-type', 'application/json');
$request->initialize(['yourParam' => 2]);
check output
检查输出
$queryParams = $request->query();
dd($queryParams['yourParam']); // 2
回答by Oleg
If you use custom requests for validation, for replace data for validation, or to set default data (for checkboxes or other) use override method prepareForValidation().
如果您使用自定义请求进行验证、替换验证数据或设置默认数据（用于复选框或其他），请使用 override method prepareForValidation()。
namespace App\Http\Requests\Admin\Category;
class CategoryRequest extends AbstractRequest
{
protected function prepareForValidation()
{
if ( ! $this->get('url')) {
$this->merge([
'url' => $this->get('name'),
]);
}
$this->merge([
'url' => Str::slug($this->get('url')),
'active' => (int)$this->get('active'),
]);
}
}
I hope this information will be useful to somebody.
我希望这些信息对某人有用。
回答by phoenix
Great answers here but I needed to replace a value in a JSON request. After a little digging into the code, I came up with the following code. Let me know if I'm doing something dumb.
这里的答案很好，但我需要替换 JSON 请求中的值。在深入研究代码后，我想出了以下代码。如果我在做一些愚蠢的事情，请告诉我。
$json = $request->json()->all();
$json['field'] = 'new value';
$request->json()->replace($json);
回答by Ja Ouad
If you need to update a property in the request, I recommend you to use the replace method from Request class used by Laravel
如果您需要更新请求中的属性，我建议您使用 Laravel 使用的 Request 类中的 replace 方法
$request->replace(['property to update' => $newValue]);
