Javascript 正则表达式报价
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/6520407/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Javascript RegEx quote
提问by cnotethegr8
I'm having trouble getting this Javascript Regular Expression to work.
What i want is to find a character that starts with @"has any characters in the middle and ends with ". I will also need it in a single quote from.
我无法让这个 Javascript 正则表达式工作。我想要的是找到一个以 开头的@"字符，中间有任何字符，以". 我还需要它在单引号中。
The tricky part for me, is that it cant be starting with @"and ending with "because the string it's looking through could look like [UIImage imageNamed:@"glass-round-red-green-button.png"].
对我来说棘手的部分是它不能以开头@"和结尾，"因为它正在查看的字符串可能看起来像[UIImage imageNamed:@"glass-round-red-green-button.png"].
So far what i have is this.
到目前为止，我所拥有的是这个。
regex: new RegExp('\\@"?\\w+\\b"*', 'g')
regex: new RegExp('\\@"?\\w+\\b"*', 'g')
回答by Gumbo
Try this regular expression:
试试这个正则表达式：
/@(["'])[^]*?/g
An explanation:
一个解释：
@(["'])matches either@"or@'[^]*?matches any arbitrary character ([^]contains all characters in opposite to.that doesn't contain line-breaks), but in a non-greedy manner\1matches the same character as matches with(["'])
@(["'])匹配@"或@'[^]*?匹配任何任意字符（[^]包含与.不包含换行符相反的所有字符），但以非贪婪的方式\1匹配与匹配相同的字符(["'])
Using the literal RegExp syntax /…/is more convenient. Note that this doesn't escape sequences like \"into account.
使用文字 RegExp 语法/…/更方便。请注意，这不会像\"考虑一样转义序列。
回答by Qtax
The regex would be:
var regex = /@"[^"]*"/g;
正则表达式将是：
var regex = /@"[^"]*"/g;
回答by Hyman Giffin
Gumbo's regexp is very nice and all, however it fails to detect escaped quotes (e.g. \", \\\", etc.). A regexp that solves this is as follows:
浓汤的正则表达式是非常好的，所有的，但它不能检测转义引号（例如\"，\\\"等）。解决这个问题的正则表达式如下：
/@(["'])[^]*?[^\](?:\\)*|@""|@''/g
An explanation (continuing from Gumbo's explanation):
一个解释（接续 Gumbo 的解释）：
[^\\]matches the nearest character preccedding the ending quote that is not a backslash (to anchor the back-slash count check).(?:\\\\)*matches only if the number of backslashes is a multiple of 2 (including zero) so that escaped backslashes are not counted.|@""checks to see if there is an empty double quote because[^\\]requires at least one character present in the string for it to work.|@''checks to see if there is an empty single quote.
[^\\]匹配不是反斜杠的结束引号之前的最近字符（以锚定反斜杠计数检查）。(?:\\\\)*仅当反斜杠的数量是 2 的倍数（包括零）时才匹配，以便不计算转义的反斜杠。|@""检查是否有空双引号，因为[^\\]字符串中至少需要一个字符才能工作。|@''检查是否有空单引号。
