ios 快速获取 UIViewController 的类名
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Get class name of UIViewController in swift
提问by Qadir Hussain
How to get class name of UIViewControllerClass in swift
如何获得的类名UIViewController在迅速类
In Objective C, we can do something like this :
在 Objective C 中，我们可以这样做：
self.appDelegate = (shAppDelegate *)[[UIApplication sharedApplication] delegate];
UIViewController *last_screen = self.appDelegate.popScreens.lastObject ;
if(last_screen.class != self.navigationController.visibleViewController.class){
//.......
}
but in swift I tried like this
但很快我就这样试过了
let appDelegate = UIApplication.sharedApplication().delegate as AppDelegate
let last_screen = appDelegate.popScreens?.lastObject as UIViewController
cant do this.
不能这样做。
if last_screen.class != self.navigationController.visibleViewController.class{
//....
}
no class method of UIViewControlleri.e last screen
没有UIViewControllerie 最后一屏的类方法
回答by juangdelvalle
To know your class name you can call something like this:
要知道您的班级名称，您可以这样调用：
var className = NSStringFromClass(yourClass.classForCoder)
回答by cnotethegr8
The cleanest way without needing to know the name of your class is like this.
不需要知道你的班级名称的最干净的方法是这样的。
let name = String(describing: type(of: self))
回答by prabhu
A simple way in swift 3 is to write the below code:
swift 3 中的一个简单方法是编写以下代码：
for instances:
为实例：
let className = String(describing: self)
for classes:
对于课程：
let className = String(describing: YourViewController.self)
回答by Isuru
Expanding on juangdelvalle's answer.
扩展 juangdelvalle 的回答。
I added this as an extension so that it's reusable and easier to call from any view controller. Also in some cases NSStringFromClassin Swift returns a string in the format like this:
我将它添加为扩展，以便它可以重用并且更容易从任何视图控制器调用。同样在某些情况下NSStringFromClass，Swift 会以如下格式返回一个字符串：
< project name >.viewControllerClassName.
< 项目名称 >.viewControllerClassName。
This extension property is modified to get rid of the project name prefix and return only the class name.
修改此扩展属性以去除项目名称前缀并仅返回类名称。
extension UIViewController {
var className: String {
return NSStringFromClass(self.classForCoder).componentsSeparatedByString(".").last!
}
}
回答by Naresh
Swift 4
斯威夫特 4
Suppose we have class with name HomeViewController. Then you can get name of class with the following code:
假设我们有 name 的类HomeViewController。然后您可以使用以下代码获取类名：
let class_name = "\(HomeViewController.classForCoder())"
The classForCoder()method returns AnyClassobject (name of your class) which we convert to string for user.
该classForCoder()方法返回AnyClass对象（您的类的名称），我们将其转换为用户的字符串。
回答by zingle-dingle
Here is a swift3 version of isuru's answer.
这是 isuru 答案的 swift3 版本。
extension UIViewController {
var className: String {
return NSStringFromClass(self.classForCoder).components(separatedBy: ".").last!;
}
}
回答by smileBot
How about:
怎么样：
extension NSObject {
static var stringFromType: String? {
return NSStringFromClass(self).components(separatedBy: ".").last
}
var stringFromInstance: String? {
return NSStringFromClass(type(of: self)).components(separatedBy: ".").last
}
}
回答by Zahidur Rahman Faisal
Use String.init(describing: self.classForCoder)
用 String.init(describing: self.classForCoder)
example:
例子：
let viewControllerName = String.init(describing: self.classForCoder)
print("ViewController Name: \(viewControllerName)")
回答by fluidsonic
The property is called dynamicTypein Swift.
该属性dynamicType在 Swift 中被调用。
