如何退出 C++ 中的 void 函数？
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How do you exit from a void function in C++?
提问by Jason Taylor
How can you prematurely exit from a function without returning a value if it is a void function? I have a void method that needs to not execute its code if a certain condition is true. I really don't want to have to change the method to actually return a value.
如果函数是 void 函数，如何在不返回值的情况下过早退出函数？我有一个 void 方法，如果某个条件为真，则不需要执行其代码。我真的不想改变方法来实际返回一个值。
回答by Mehrdad Afshari
Use a return statement!
使用返回语句！
return;
or
或者
if (condition) return;
You don't need to (and can't) specify any values, if your method returns void.
如果您的方法返回void.
回答by jwfearn
You mean like this?
你的意思是这样？
void foo ( int i ) {
if ( i < 0 ) return; // do nothing
// do something
}
回答by Stephen Caldwell
void foo() {
/* do some stuff */
if (!condition) {
return;
}
}
You can just use the return keyword just like you would in any other function.
您可以像在任何其他函数中一样使用 return 关键字。
回答by Amal K
I know the question is already answered and using a returnstatement does the job.
But alternatively you can also include the rest of the function in the elseblock of the ifcondition.
我知道这个问题已经得到了回答，使用return声明就可以了。但是，您也可以else在if条件块中包含函数的其余部分。
