在 Java 中对单个字符串进行排序
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/605891/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Sort a single String in Java
提问by
Is there a native way to sort a String by its contents in java? E.g.
有没有一种本地方法可以按 Java 中的内容对字符串进行排序？例如
String s = "edcba" -> "abcde"
回答by Jon Skeet
toCharArrayfollowed by Arrays.sortfollowed by a String constructor call:
toCharArray后跟Arrays.sort一个 String 构造函数调用：
import java.util.Arrays;
public class Test
{
public static void main(String[] args)
{
String original = "edcba";
char[] chars = original.toCharArray();
Arrays.sort(chars);
String sorted = new String(chars);
System.out.println(sorted);
}
}
EDIT: As tackline points out, this will fail if the string contains surrogate pairs or indeed composite characters (accent + e as separate chars) etc. At that point it gets a lot harder... hopefully you don't need this :) In addition, this is just ordering by ordinal, without taking capitalisation, accents or anything else into account.
编辑：正如tackline所指出的，如果字符串包含代理对或复合字符（重音+ e作为单独的字符）等，这将失败。在这一点上它变得更加困难......希望你不需要这个:)此外，这只是按序数排序，没有考虑大小写、重音或其他任何因素。
回答by eljenso
No there is no built-in String method. You can convert it to a char array, sort it using Arrays.sort and convert that back into a String.
不，没有内置的 String 方法。您可以将其转换为字符数组，使用 Arrays.sort 对其进行排序并将其转换回字符串。
String test= "edcba";
char[] ar = test.toCharArray();
Arrays.sort(ar);
String sorted = String.valueOf(ar);
Or, when you want to deal correctly with locale-specific stuff like uppercase and accented characters:
或者，当您想正确处理特定于语言环境的内容（如大写和重音字符）时：
import java.text.Collator;
import java.util.Arrays;
import java.util.Comparator;
import java.util.Locale;
public class Test
{
public static void main(String[] args)
{
Collator collator = Collator.getInstance(new Locale("fr", "FR"));
String original = "éDedCBcbAàa";
String[] split = original.split("");
Arrays.sort(split, collator);
String sorted = "";
for (int i = 0; i < split.length; i++)
{
sorted += split[i];
}
System.out.println(sorted); // "aAàbBcCdDeé"
}
}
回答by amit
String a ="dgfa";
char [] c = a.toCharArray();
Arrays.sort(c);
return new String(c);
Note that this will not work as expected if it is a mixed case String (It'll put uppercase before lowercase). You can pass a comparator to the Sort method to change that.
请注意，如果它是大小写混合的字符串（它将大写放在小写之前），则这将无法按预期工作。您可以将比较器传递给 Sort 方法来改变它。
回答by agaase
A more raw approach without using sort Arrays.sort method. This is using insertion sort.
一种更原始的方法，不使用 sort Arrays.sort 方法。这是使用插入排序。
public static void main(String[] args){
String wordSt="watch";
char[] word=wordSt.toCharArray();
for(int i=0;i<(word.length-1);i++){
for(int j=i+1;j>0;j--){
if(word[j]<word[j-1]){
char temp=word[j-1];
word[j-1]=word[j];
word[j]=temp;
}
}
}
wordSt=String.valueOf(word);
System.out.println(wordSt);
}
回答by Maroun
Convert to array of chars→ Sort→ Convert back to String:
String s = "edcba";
char[] c = s.toCharArray(); // convert to array of chars
java.util.Arrays.sort(c); // sort
String newString = new String(c); // convert back to String
System.out.println(newString); // "abcde"
回答by Marcin
In Java 8 it can be done with:
在 Java 8 中，它可以通过以下方式完成：
String s = "edcba".chars()
.sorted()
.collect(StringBuilder::new, StringBuilder::appendCodePoint, StringBuilder::append)
.toString();
A slightly shorter alternative that works with a Stream of Strings of length one (each character in the unsorted String is converted into a String in the Stream) is:
与长度为 1 的字符串流（未排序的字符串中的每个字符都转换为流中的字符串）一起使用的稍短的替代方法是：
String sorted =
Stream.of("edcba".split(""))
.sorted()
.collect(Collectors.joining());
回答by rashedcs
Procedure :
程序 ：
- At first convert the string to char array
- Then sort the array of character
- Convert the character array to string
- Print the string
- 首先将字符串转换为字符数组
- 然后对字符数组进行排序
- 将字符数组转换为字符串
- 打印字符串
Code snippet:
代码片段：
String input = "world";
char[] arr = input.toCharArray();
Arrays.sort(arr);
String sorted = new String(arr);
System.out.println(sorted);
回答by Tarun Jadhav
public static void main(String[] args) {
String str = "helloword";
char[] arr;
List<Character> l = new ArrayList<Character>();
for (int i = 0; i < str.length(); i++) {
arr = str.toCharArray();
l.add(arr[i]);
}
Collections.sort(l);
str = l.toString();
System.out.println(str);
str = str.replaceAll("\[", "").replaceAll("\]", "")
.replaceAll("[,]", "");
System.out.println(str);
}
回答by naveen prasanna
Without using Collections in Java:
在 Java 中不使用集合：
import java.util.Scanner;
public class SortingaString {
public static String Sort(String s1)
{
char ch[]=s1.toCharArray();
String res=" ";
for(int i=0; i<ch.length ; i++)
{
for(int j=i+1;j<ch.length; j++)
{
if(ch[i]>=ch[j])
{
char m=ch[i];
ch[i]=ch[j];
ch[j]=m;
}
}
res=res+ch[i];
}
return res;
}
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
System.out.println("enter the string");
String s1=sc.next();
String ans=Sort( s1);
System.out.println("after sorting=="+ans);
}
}
Output:
输出：
enter the string==
sorting
after sorting== ginorst
输入字符串==
排序
排序后== ginorst
回答by Soudipta Dutta
Question: sort a string in java
问题：在java中对字符串进行排序
public class SortAStringInJava {
public static void main(String[] args) {
String str = "Protijayi";
// Method 1
str = str.chars() // IntStream
.sorted().collect(StringBuilder::new, StringBuilder::appendCodePoint, StringBuilder::append).toString();
System.out.println(str);
// Method 2
str = Stream.of(str.split(" ")).sorted().collect(Collectors.joining());
System.out.println(str);
}
}
