javascript 删除不需要的字符串部分。正则表达式/JS
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Remove unwanted part of String. Regex / JS
提问by Daft
If I have a string which looks like this:
如果我有一个看起来像这样的字符串：
var myString = '73gf9y::-8auhTHIS_IS_WHAT_I_WANT'
What regex would I need to end up with:
我最终需要什么正则表达式：
'THIS_IS_WHAT_I_WANT'
The first part of my String will always be a random assortment of characters. Is there some regex which will remove everything up to THIS?
我的字符串的第一部分将始终是随机分类的字符。是否有一些正则表达式可以删除所有内容THIS？
回答by Jonny 5
So you want to strip out everything from beginning to the first uppercase letter?
所以你想去掉从开头到第一个大写字母的所有内容？
console.log(myString.replace(/^[^A-Z]+/,""));
THIS_IS_WHAT_I_WANT
这就是我要的
See fiddle, well I'm not sure if that is what you want :)
看小提琴，我不确定这是否是你想要的:)
To strip out everything from start to the first occuring uppercase string, that's followed by _try:
要删除从开始到第一个出现的大写字符串的所有内容，然后_尝试：
myString.replace(/^.*?(?=[A-Z]+_)/,"");
This uses a lookahead. See Test at regex101;
这使用了前瞻。参见regex101 处的测试；
回答by Amit Joki
Going by the input, you can use match. The character class [A-Z_]matches any capital letters and _(Underscore) and +quantifier along with $anchor matches the character class till the end of the string.
根据输入，您可以使用match. 字符类[A-Z_]匹配任何大写字母和_（下划线）和+量词以及$锚点匹配字符类直到字符串的末尾。
myString = myString.match(/[A-Z_]+$/)[0];
console.log(myString); // THIS_IS_WHAT_I_WANT
回答by TobyRush
Adding to Amit Joki's excellent solution (sorry I don't have the rep yet to comment): since matchreturns an array of results, if you need to remove unwanted characters from within the string, you can use join:
添加到 Amit Joki 的优秀解决方案（抱歉，我还没有代表发表评论）：由于match返回结果数组，如果您需要从字符串中删除不需要的字符，您可以使用join：
input = '(800) 555-1212';
result = input.match(/[0-9]+/g).join('');
console.log(result); // '8005551212'
