javascript jquery中具有有限特殊字符的正则表达式
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/21164978/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
regular expression with limited special characters in jquery
提问by patel
I would like to all alphanumeric data + only these following 4 special character are allowed.
我想所有字母数字数据 + 只允许以下 4 个特殊字符。
' (single quote)
- (hyphen)
. (dot)
single space
I tried this :
我试过这个：
var userinput = $(this).val();
var pattern = [A-Za-z0-9_~\-!@#$%\^&\*\(\)]+$
if(!pattern.test(userinput))
{
alert('not a valid');
}?
but it is not working.
但它不起作用。
回答by Stefano Sanfilippo
First, you need to enclose the string in /to have it interpreted as a regex:
首先，您需要将字符串括起来/以将其解释为正则表达式：
var pattern = /[A-Za-z0-9_~\-!@#$%\^&\*\(\)]+$/;
Then, you have to remove some unallowed characters (that regex is matching more than you specified):
然后，您必须删除一些不允许的字符（该正则表达式匹配的比您指定的多）：
var pattern = /^[A-Za-z0-9 '.-]+$/;
The second one is what you need. Complete code:
第二个是你需要的。完整代码：
var userinput = $(this).val();
var pattern = /^[A-Za-z0-9 '.-]+$/;
if(!pattern.test(userinput))
{
alert('not a valid');
}?
Besides, check what thispoints to.
此外，检查this指向什么。
回答by npst
"Not working" is not a helpful description of your problem.
“不工作”对您的问题没有帮助。
I'd suggest this regular expresion:
我建议这个正则表达式：
^[a-zA-Z0-9\'\-\. ]+$
