Javascript 正则表达式精确匹配 5 位数字
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regular expression to match exactly 5 digits
提问by i need help
testing= testing.match(/(\d{5})/g);
I'm reading a full html into variable. From the variable, want to grab out all numbers with the pattern of exactly 5 digits. No need to care of whether before/after this digit having other type of words. Just want to make sure whatever that is 5 digit numbers been grabbed out.
我正在将完整的 html 读入变量。从变量中，要抓取所有具有恰好 5 位数字的模式的数字。无需关心此数字之前/之后是否有其他类型的单词。只是想确保任何 5 位数字都被抓取了。
However, when I apply it, it not only pull out number with exactly 5 digit, number with more than 5 digits also retrieved...
但是，当我应用它时，它不仅提取出正好为 5 位的数字，而且还检索到了 5 位以上的数字...
I had tried putting ^in front and $behind, but it making result come out as null.
我曾尝试^在前后放置$，但它使结果显示为空。
回答by alex
I am reading a text file and want to use regex below to pull out numbers with exactly 5 digit, ignoring alphabets.
我正在阅读一个文本文件，并想使用下面的正则表达式来提取 5 位数字，忽略字母。
Try this...
尝试这个...
var str = 'f 34 545 323 12345 54321 123456',
matches = str.match(/\b\d{5}\b/g);
console.log(matches); // ["12345", "54321"]
The word boundary \bis your friend here.
边界这个词\b是你的朋友。
Update
更新
My regex will get a number like this 12345, but notlike a12345. The other answers provide great regexes if you require the latter.
我的正则表达式会得到这样的数字12345，但不会像a12345. 如果您需要后者，其他答案提供了很好的正则表达式。
回答by outis
My test string for the following:
我的测试字符串如下：
testing='12345,abc,123,54321,ab15234,123456,52341';
If I understand your question, you'd want ["12345", "54321", "15234", "52341"].
如果我理解你的问题，你会想要["12345", "54321", "15234", "52341"].
If JS engines supported regexp lookbehinds, you could do:
如果 JS 引擎支持 regexp lookbehinds，你可以这样做：
testing.match(/(?<!\d)\d{5}(?!\d)/g)
Since it doesn't currently, you could:
由于目前没有，您可以：
testing.match(/(?:^|\D)(\d{5})(?!\d)/g)
and remove the leading non-digit from appropriate results, or:
并从适当的结果中删除前导非数字，或：
pentadigit=/(?:^|\D)(\d{5})(?!\d)/g;
result = [];
while (( match = pentadigit.exec(testing) )) {
result.push(match[1]);
}
Note that for IE, it seems you need to use a RegExp stored in a variablerather than a literal regexp in the whileloop, otherwise you'll get an infinite loop.
请注意，对于 IE，似乎您需要使用存储在变量中的RegExp而不是while循环中的文字 regexp ，否则您将获得无限循环。
回答by Mark Eirich
This should work:
这应该有效：
<script type="text/javascript">
var testing='this is d23553 test 32533\n31203 not 333';
var r = new RegExp(/(?:^|[^\d])(\d{5})(?:$|[^\d])/mg);
var matches = [];
while ((match = r.exec(testing))) matches.push(match[1]);
alert('Found: '+matches.join(', '));
</script>
回答by Luke
what is about this? \D(\d{5})\D
这是怎么回事？ \D(\d{5})\D
This will do on:
这将用于：
f 23 23453 234 2344 2534 hallo33333 "50000"
f 23 23453 234 2344 2534 halo33333 “50000”
23453, 33333 50000
23453、33333 50000
回答by Muhammad Saqib
No need to care of whether before/after this digit having other type of words
无需关心此数字之前/之后是否有其他类型的单词
To just match the pattern of 5 digits number anywhere in the string, no matter it is separated by space or not, use this regular expression (?<!\d)\d{5}(?!\d).
要匹配字符串中任意位置的 5 位数字的模式，无论是否以空格分隔，都使用此正则表达式(?<!\d)\d{5}(?!\d)。
Sample JavaScript codes:
示例 JavaScript 代码：
var regexp = new RegExp(/(?<!\d)\d{5}(?!\d)/g);
var matches = yourstring.match(regexp);
if (matches && matches.length > 0) {
for (var i = 0, len = matches.length; i < len; i++) {
// ... ydo something with matches[i] ...
}
}
Here's some quick results.
这是一些快速的结果。
abc12345xyz (?)
12345abcd (?)
abcd12345 (?)
0000aaaa2 (?)
a1234a5 (?)
12345 (?)
<space>12345<space>12345 (??)
abc12345xyz (?)
12345abcd (?)
abcd12345 (?)
0000aaaa2 (?)
a1234a5 (?)
12345（？）
<space>12345<space>12345 (??)
