php 解析错误:语法错误,第 5 行出现意外的 T_VARIABLE

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时间:2020-08-25 03:08:43  来源:igfitidea点击:

Parse error: syntax error, unexpected T_VARIABLE on line 5

phpsqlwordpress

提问by John Conde

I am new to PHP and am encountering this parsing error. My code is:

我是 PHP 新手,遇到了这个解析错误。我的代码是:

 <?php
   $con=mysqli_connect("glcmcrusaders.ipagemysql.com", "cycregister", "Crusaders13!",          
    "registration")


    $sql="INSERT INTO camperregistration (camperFirstName, camperLastName, camperGender,       
    camperBirthdate, camperStreet, camperCity, camperState, camperZip, camperCountry,   
    camperShirtSize, guardianFirstName, guardianLastName, guardianStreet, guardianCity,  
    guardianState, guardianZip, guardianCountry, guardianCell, guardianEmail,  
    alternateFirstName, alternateLastName, alternateStreet, alternateCity, alternateState, 
    alternateZip, alternateCountry, alternateCell, alternateRelationship, camperSwimming)
    VALUES 
    ('$_POST[camperFirstName]', '$_POST[camperLastName]', '$_POST[camperGender]',     
    '$_POST[camperBirthdate]', '$_POST[camperStreet]', '$_POST[camperCity]',   
    '$_POST[camperState]', '$_POST[camperZip]', '$_POST[camperCountry]',  
    '$_POST[camperShirtSize]', '$_POST[guardianFirstName]', '$_POST[guardianLastName]', 
    '$_POST[guardianStreet]', '$_POST[guardianZip]', '$_POST[guardianCountry]', 
    '$_POST[guardianCell]', '$_POST[guardianEmail]', '$_POST[alternateFirstName]', 
    '$_POST[alternateLastName]', '$_POST[alternateStreet]', '$_POST[alternateCity]',
    '$_POST[alternateState]', '$_POST[alternateZip]', '$_POST[alternateCountry]',  
    '$_POST[alternateCell]', '$_POST[alternateRelationship]', '$_POST[camperSwimming]')";

     mysqli_close($con);
     ?>

Line 5 starts at the %sql ="INSERT INTO... ends at camperSwimming) I am not sure what I am doing wrong.

第 5 行开始于 %sql ="INSERT INTO... 结束于 camperSwimming) 我不确定我做错了什么。

回答by John Conde

Missing a semi-colon:

缺少分号:

$con=mysqli_connect("glcmcrusaders.ipagemysql.com", "cycregister", "Crusaders13!",          
"registration") // <-- HERE

回答by Moeed Farooqui

you need a terminator(;)at the end of $con.

你需要terminator(;)$con.

$con=mysqli_connect("glcmcrusaders.ipagemysql.com", "cycregister", "Crusaders13!",          
    "registration");
                   ^Here