Ruby-on-rails link_to 路径定义
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link_to path definition
提问by Mellon
I am developoing a Rails v2.3.2app.
我正在开发一个Rails v2.3.2应用程序。
I have a controller:
我有一个控制器：
class SchoolController < ApplicationController
...
def edit
@school=School.find_by_id params[:id]
end
def check_teachers
@teachers = @school.teachers
...
end
end
in app/views/schools/edit.html.erbI would like to have a link, click on it will trigger the check_teachersmethod in the controller, how to define the pathfor this link?
在app/views/schools/edit.html.erb我想有一个link，点击它会触发check_teachers该方法控制器，如何定义路径为这个link？
app/views/schools/edit.html.erb :
app/views/schools/edit.html.erb ：
link_to 'Check teachers' WHAT_IS_THE_PATH_HERE
回答by rubyprince
link_to 'Check teachers', :action => :check_teachers, :id => @school.id
or
或者
link_to 'Check teachers', "/school/check_teachers/#{@school.id}"
or you can define a named-route in config/routes.rblike this:
或者你可以config/routes.rb像这样定义一个命名路由：
map.check_teachers, '/school/check_teachers/:id' :controller => :school, :action => :check_teachers
and call the url-helper generated by the named-route like this:
并像这样调用由命名路由生成的 url-helper：
link_to 'Check teachers', check_teachers_path(:id => @school.id)
and you can use this id to find teachers in the controller
您可以使用此 ID 在控制器中查找教师
def check_teachers
@school = School.find params[:id]
@teachers = @school.teachers
...
end
回答by Chuck Callebs
You can define something like this in your routes.rbfile.
您可以在routes.rb文件中定义类似的内容。
map.connect "schools/:id/check_teachers", :controller => "schools", :action => "check_teachers"
You'd then set up your link_toas follows:
然后，您link_to将按如下方式设置：
link_to "Check teachers", check_teachers_path(:id => @school.id)
You'll need to add this bit of code into the controller, as model states aren't shared between controller actions:
您需要将这段代码添加到控制器中，因为模型状态不会在控制器操作之间共享：
def check_teachers
@school = School.find_by_id(params[:id])
# Then you can access the teachers with @school.teachers
end
This is untested but should work. Just comment if you have any further issues.
这是未经测试的，但应该可以工作。如果您有任何进一步的问题，请发表评论。
