java XStream：具有属性和文本节点的节点？
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XStream : node with attributes and text node?
提问by subb
I would like to serialize an object to an XML of this form with XStream.
我想使用 XStream 将对象序列化为这种形式的 XML。
<node att="value">text</node>
The value of the node (text) is a field on the serialized object, as well as the attattribute. Is this possible without writing a converter for this object?
节点 ( text)的值是序列化对象上的一个字段，以及att属性。如果不为此对象编写转换器，这可能吗？
Thanks!
谢谢！
采纳答案by Kiru
write a convertor, it should be something similar to the code snippet
写一个转换器，它应该类似于代码片段
class FieldDtoConvertor implements Converter {
@SuppressWarnings("unchecked")
public boolean canConvert(final Class clazz) {
return clazz.equals(FieldDto.class);
}
public void marshal(final Object value,
final HierarchicalStreamWriter writer,
final MarshallingContext context) {
final FieldDto fieldDto = (FieldDto) value;
writer.addAttribute(fieldDto.getAttributeName(), fieldDto.getAttributeValue());
}
}
And while using XStream,register the convertor
并在使用 XStream 时，注册转换器
final XStream stream = new XStream(new DomDriver());
stream.registerConverter(new FieldDtoConvertor());
回答by mantrid
you can use a predefined Converter.
您可以使用预定义的转换器。
@XStreamAlias("node")
@XStreamConverter(value=ToAttributedValueConverter.class, strings={"text"})
class Node {
private String att;
private String text;
}
XStream Annotations Tutorialalso says that for attattribute:
XStream Annotations Tutorial也说对于att属性：
Note, that no XStreamAsAttribute annotations were necessary. The converter assumes it implicitly.
请注意，不需要 XStreamAsAttribute 注释。转换器隐式地假定它。
回答by bdoughan
This is much easier in JAXB
这在 JAXB 中要容易得多
@XmlRootElement
public class Node {
@XmlAttribute
String att;
@XmlValue
String value;
}
回答by Thomas
Just another way of doing it:
只是另一种方式：
@XStreamAlias("My")
private static class My {
private String field;
}
XStream xStream = new XStream();
xStream.autodetectAnnotations(true);
xStream.useAttributeFor(My.class, "field");
