javascript 使用 Browserify 编译动态需要的模块
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Compiling dynamically required modules with Browserify
提问by Brad
I am using Browserify to compile a large Node.js application into a single file (using options --bareand --ignore-missing[to avoid troubles with lib-covin Express]). I have some code to dynamically load modules based on what is available in a directory:
我正在使用 Browserify 将大型 Node.js 应用程序编译成单个文件（使用选项--bare和--ignore-missing[避免lib-cov在 Express 中出现问题]）。我有一些代码可以根据目录中的可用内容动态加载模块：
var fs = require('fs'),
path = require('path');
fs.readdirSync(__dirname).forEach(function (file) {
if (file !== 'index.js' && fs.statSync(path.join(__dirname, file)).isFile()) {
module.exports[file.substring(0, file.length-3)] = require(path.join(__dirname, file));
}
});
I'm getting strange errors in my application where aribtrary text files are being loaded from the directory my compiled file is loaded in. I think it's because paths are no longer set correctly, and because Browserify won't be able to require()the correct files that are dynamically loaded like this.
我在我的应用程序中遇到奇怪的错误，其中从我的编译文件加载的目录加载了任意文本文件。我认为这是因为路径设置不再正确，并且因为 Browserify 将无法require()正确的文件像这样动态加载。
Short of making a static index.jsfile, is there a preferred method of dynamically requiring a directory of modules that is out-of-the-box compatible with Browserify?
index.js除了制作静态文件之外，是否有一种首选方法可以动态要求与 Browserify 开箱即用的模块目录？
回答by mjlescano
This plugin allows to require Glob patterns: require-globify
这个插件允许 require Glob 模式：require-globify
Then, with a little hack you can add all the files on compilation and not executing them:
然后，通过一些小技巧，您可以在编译时添加所有文件而不执行它们：
// Hack to compile Glob files. Don′t call this function!
function ?_?()?{
require('views/**/*.js', { glob: true })
}
And, for example, you could require and execute a specific file when you need it :D
并且，例如，您可以在需要时要求并执行特定文件：D
var homePage = require('views/'+currentView)
回答by Miroslav Bajto?
Browserify does not support dynamic requires - see GH issue 377.
Browserify 不支持动态要求 - 请参阅GH 问题 377。
The only method for dynamically requiring a directory I am aware of: a build step to list the directory files and write the "static" index.js file.
我所知道的动态需要目录的唯一方法：列出目录文件并编写“静态”index.js 文件的构建步骤。
回答by Christopher Davies
There's also the bulkifytransform, as documented here:
还有bulkify转换，如此处所述：
https://github.com/chrisdavies/tech-thoughts/blob/master/browserify-include-directory.md
https://github.com/chrisdavies/tech-thoughts/blob/master/browserify-include-directory.md
Basically, you can do this in your app.jsor whatever:
基本上，您可以在您的app.js或其他任何内容中执行此操作：
var bulk = require('bulk-require');
// Require all of the scripts in the controllers directory
bulk(__dirname, ['controllers/**/*.js']);
And my gulpfile has something like this in it:
我的 gulpfile 中有这样的内容：
gulp.task('js', function () {
return gulp.src('./src/js/init.js')
.pipe(browserify({
transform: ['bulkify']
}))
.pipe(rename('app.js'))
.pipe(uglify())
.pipe(gulp.dest('./dest/js'));
});
