Bash 函数参数返回错误“找不到命令”
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Bash function argument returns error "command not found"
提问by JKirchartz
I have this function in a bash script, to create a new jekyll post; but it returns the argument as command not found. Here's the script:
我在 bash 脚本中有这个功能，可以创建一个新的 jekyll 帖子；但它将参数作为未找到的命令返回。这是脚本：
function new_post () {
if [ -z "" ]
then
read -p "Post Title:" TITLE
else
TITLE= ""
fi
FILE=$( echo $TITLE | tr A-Z a-z | tr ' ' _ )
echo -e '---\nlayout: post\ntitle: '$TITLE'\npublished: false\n---\n' > $(date '+%Y-%m-%d-')"$FILE"'.md'
}
But whenever I try to run it it returns:
但是每当我尝试运行它时，它都会返回：
$>new_post "Hello World"
-bash: Hello World: command not found
It appears to be trying to run the argument as a command.
它似乎试图将参数作为命令运行。
I even tried this and got the same result
我什至尝试了这个并得到了相同的结果
$>TITLE= "Hello World" && echo -e ---layout: post\ntitle: "$TITLE"\n---
-bash: Hello World: command not found
Can anybody tell me what I'm doing wrong?
谁能告诉我我做错了什么？
回答by phsym
It may be the space in TITLE= "$1"that causes the error. Try with TITLE="$1"
它可能是TITLE= "$1"导致错误的空间。试试TITLE="$1"
回答by Greg Woz
In my case:
就我而言：
echo "Deploy of `` to `` project? (Y/N)"
the issue was also present. When I removed [``] it's gone. Not sure if you pasted a complete script but beware double quotes for args.
这个问题也存在。当我删除 [``] 时，它就消失了。不确定您是否粘贴了完整的脚本，但要注意 args 的双引号。
Similar answer https://askubuntu.com/questions/180320/bash-script-program-with-parameters-as-a-single-variable-command-not-found
