C#创建类的实例并按字符串中的名称设置属性
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C# creating instance of class and set properties by name in string
提问by Adrian Ksi??arczyk
I have some problem. I want to creating instance of class by name.
I found Activator.CreateInstancehttp://msdn.microsoft.com/en-us/library/d133hta4.aspxand it works fine, and I found this:
Setting a property by reflection with a string valuetoo.
我有一些问题。我想按名称创建类的实例。我找到了Activator.CreateInstancehttp://msdn.microsoft.com/en-us/library/d133hta4.aspx并且它工作正常，我发现了这一点：
通过反射设置一个字符串值的属性。
But how to do both od this? I mean, I know the name of class, I know all properties in that class and I have this in string. For example:
但是如何做到这一点呢？我的意思是，我知道类的名称，我知道该类中的所有属性，并且我将其放在字符串中。例如：
string name = "MyClass";
string property = "PropertyInMyClass";
How to create instance and set some value to properties ?
如何创建实例并为属性设置一些值？
采纳答案by Darin Dimitrov
You could use Reflection:
你可以使用反射：
using System;
using System.Reflection;
public class Foo
{
public string Bar { get; set; }
}
public class Program
{
static void Main()
{
string name = "Foo";
string property = "Bar";
string value = "Baz";
// Get the type contained in the name string
Type type = Type.GetType(name, true);
// create an instance of that type
object instance = Activator.CreateInstance(type);
// Get a property on the type that is stored in the
// property string
PropertyInfo prop = type.GetProperty(property);
// Set the value of the given property on the given instance
prop.SetValue(instance, value, null);
// at this stage instance.Bar will equal to the value
Console.WriteLine(((Foo)instance).Bar);
}
}
回答by Tomá? Václavík
If you had System.TypeLoad Exception, your class name is wrong.
如果您有 System.TypeLoad 异常，则您的类名是错误的。
To method Type.GetType you must enter assembly-qualified name. That is with the project name For example: GenerateClassDynamically_ConsoleApp1.Foo
要使用 Type.GetType 方法，您必须输入程序集限定名称。即与项目名称例如：GenerateClassDynamically_ConsoleApp1.Foo
If it is in another assembly jou must enter assembly name after comma (details on https://stackoverflow.com/a/3512351/1540350): Type.GetType("GenerateClassDynamically_ConsoleApp1.Foo,GenerateClassDynamically_ConsoleApp1");
如果它在另一个程序集中，则必须在逗号后输入程序集名称（详情见https://stackoverflow.com/a/3512351/1540350）： Type.GetType("GenerateClassDynamically_ConsoleApp1.Foo,GenerateClassDynamically_ConsoleApp1");
回答by Hanan
Type tp = Type.GetType(Namespace.class + "," + n.Attributes["ProductName"].Value + ",Version=" + n.Attributes["ProductVersion"].Value + ", Culture=neutral, PublicKeyToken=null");
if (tp != null)
{
object o = Activator.CreateInstance(tp);
Control x = (Control)o;
panel1.Controls.Add(x);
}
