javascript 未捕获的类型错误：无法读取简单 JSON 数组的未定义属性“长度”
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Uncaught TypeError: Cannot read property 'length' of undefined for simple JSON array
提问by victorvictord
I am calling a function this way .
我正在以这种方式调用函数。
var responseinner = returnvalues(selectedeleemnt);
console.log(responseinner);
displaying as Object
显示为对象
console.log(JSON.stringify(responseinner));
displaying as[{"name":"Coke","image":"json_images/coke_can.jpg","type":["250ml","300ml"],"price":["50","60"]}]
显示为[{"name":"Coke","image":"json_images/coke_can.jpg","type":["250ml","300ml"],"price":["50","60"]}]
I tried all the ways of parsing this value
我尝试了所有解析这个值的方法
[{"name":"Coke","image":"json_images/coke_can.jpg","type":["250ml","300ml"],"price":["50","60"]}]
But always it throws the error as
但它总是抛出错误
Uncaught TypeError: Cannot read property 'length' of undefined
未捕获的类型错误：无法读取未定义的属性“长度”
I used JSON.parse , JSON.stringfy() . but none helped .
我使用了 JSON.parse ， JSON.stringfy() 。但没有帮助。
for (var i = 0; i < responseinner.type.length; i++) {
}
could anybody please help me
有人可以帮我吗
回答by victorvictord
for(var i=0;i<responseinner.length;i++){
responseinner[i].type .... }
for(var i=0;i<responseinner.length;i++){
responseinner[i].type .... }
回答by Amit Joki
Your responseinnerisn't an Objectbut an Arraywith only one element.
你responseinner不是一个，Object而是一个Array只有一个元素。
So, you'll have to use responseinner[0].type.length
所以，你必须使用 responseinner[0].type.length
If it was an object, it would have started with {}and not [], with what arrays start.
如果它是一个对象，它将以数组开头{}而不是[]开头。
回答by Aboca
To parse json with jquery:
使用 jquery 解析 json：
$.each($.parseJSON(responseinner), function(key,value){
//do something
});
If responseinner is already formed as a json you don't need the $.parseJSON
如果 responseinner 已经形成为一个 json 你不需要 $.parseJSON
or
或者
responseineer[0].name
responseineer[0].image
...
Json data comes into an array so get it's object with an index, so to access it: responseineer[0]
Json 数据进入一个数组，因此使用索引获取它的对象，以便访问它： responseineer[0]
回答by theClap
try test[0].type.lengthyou have an Object in an array of length 1 therefore you must first define the index location of the Object in the array which is trivial since the array has 1 defined index.
尝试test[0].type.length在长度为 1 的数组中有一个对象，因此您必须首先在数组中定义对象的索引位置，这是微不足道的，因为数组有 1 个定义的索引。
for (var i = 0; i < responseinner[0].type.length; i++) {
}
回答by Vinoth Narayan
for(var i=0;i
for(var i=0;i
Its works fine but...how to assign to gridview in client side
它工作正常但是......如何在客户端分配给gridview
