如何在 JavaScript 中获取不带任何参数的 URL？
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How to get the URL without any parameters in JavaScript?
提问by Tyler
If I use:
如果我使用：
alert(window.location.href);
I get everything including query strings. Is there a way to just get the main url part, for example:
我得到了包括查询字符串在内的所有内容。有没有办法只获取主 url 部分，例如：
http://mysite.com/somedir/somefile/
instead of
代替
http://mysite.com/somedir/somefile/?foo=bar&loo=goo
回答by lonesomeday
This is possible, but you'll have to build it manually from the locationobject:
这是可能的，但您必须从location对象手动构建它：
location.protocol + '//' + location.host + location.pathname
回答by Oddman
Every answer is rather convoluted. Here:
每个答案都相当复杂。这里：
var url = window.location.href.split('?')[0];
Even if a ? isn't present, it'll still return the first argument, which will be your full URL, minus query string.
即使一个 ? 不存在，它仍然会返回第一个参数，这将是您的完整 URL，减去查询字符串。
It's also protocol-agnostic, meaning you could even use it for things like ftp, itunes.etc.
它也是协议不可知的，这意味着你甚至可以将它用于诸如 ftp、itunes.etc 之类的东西。
回答by Niklas
Use indexOf
用 indexOf
var url = "http://mysite.com/somedir/somefile/?aa";
if (url.indexOf("?")>-1){
url = url.substr(0,url.indexOf("?"));
}
回答by Headshota
var url = "tp://mysite.com/somedir/somefile/?foo=bar&loo=goo"
url.substring(0,url.indexOf("?"));
回答by Mic
You can use a regular expression: window.location.href.match(/^[^\#\?]+/)[0]
您可以使用正则表达式： window.location.href.match(/^[^\#\?]+/)[0]
回答by AamirR
You can concat originand pathname, if theres present a port such as example.com:80, that will be included as well.
您可以连接origin和pathname，如果存在诸如 之类的端口example.com:80，则也将包含该端口。
location.origin + location.pathname
回答by planetjones
If you look at the documentationyou can take just the properties you're interested in from the windowobject i.e.
如果您查看文档，您可以只从window对象中获取您感兴趣的属性，即
protocol + '//' + hostname + pathname
