Java 中的 RestTemplate - RestTemplate 没有足够的变量值
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/33214059/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
RestTemplate in Java - Not enough variable values available with RestTemplate
提问by stack man
I've got the following:
我有以下几点：
final String notification = "{\"DATA\"}";
final String url = "http://{DATA}/create";
ResponseEntity<String> auth = create(address, name, psswd, url);
Attacking this method:
攻击这个方法：
private ResponseEntity<String> create(final String address, final String name,
final String newPassword, final String url) {
final Map<String, Object> param = new HashMap<>();
param.put("name", name);
param.put("password", newPassword);
param.put("email", address);
final HttpHeaders header = new HttpHeaders();
final HttpEntity<?> entity = new HttpEntity<Object>(param, header);
RestTemplate restTemplate = new RestTemplate();
return restTemplate.postForEntity(url, entity, String.class);
}
I think it should work, but it's throwing me a
我认为它应该有效，但它让我感到
org.springframework.web.util.NestedServletException: Request processing failed; nested exception is java.lang.IllegalArgumentException: Not enough variable values available to expand 'notification'
Why?
为什么？
回答by ESala
As the duplicates of your question say, you have { }in your URL.
正如您的问题的重复项所说，您{ }的网址中有。
Spring will try to fill that {notification}but since you don't provide it, it fails saying Not enough variable values available to expand 'notification'.
Spring 将尝试填充它，{notification}但由于您不提供它，因此它无法说Not enough variable values available to expand 'notification'.
You just need to pass the notification string so that Spring can build the URL correctly.
您只需要传递通知字符串，以便 Spring 可以正确构建 URL。
Here is the javadocfor this method:
这是此方法的javadoc：
public <T> ResponseEntity<T> postForEntity(String url,
Object request,
Class<T> responseType,
Object... uriVariables)
throws RestClientException
Parameters:
url - the URL
request - the Object to be POSTed, may be null
responseType - the class of the response
uriVariables - the variables to expand the template
So, you need to pass the notification string as a 4th parameter, like this:
因此，您需要将通知字符串作为第四个参数传递，如下所示：
restTemplate.postForEntity(url, entity, String.class, notification);
回答by stack man
The following line was just enough to get it working. I got rid of the key characters and it's working now.
以下行足以让它工作。我摆脱了关键角色，现在可以使用了。
final String url = "http://DATA/create";
