PHP MYSQL 加入查询。SELECT WHERE AND IN OR 逻辑错误

PHP MYSQL Join Query. SELECT WHERE AND IN OR Logic Error

提问by Newphper

Hey all. I think I have a logic error in my qry. The output is correct but in triplets. I've been staring at this for a long time and not seeing it. Can someone shed some light on this? Thanks!!

大家好。我想我的 qry 中有逻辑错误。输出是正确的，但在三元组中。我一直盯着这个很长时间，没有看到它。有人可以对此有所了解吗？谢谢！！

Also wanted to add this info as well.

也想添加此信息。

• $userid = 1
• $UserIDAList = (1,1,6)
• $UserIDBList = (2,3,1)

• $userid = 1
• $UserIDAList = (1,1,6)
• $UserIDBList = (2,3,1)

PHP-Code:

PHP-代码：

$result  = mysql_query("SELECT TBL_ContactsList.ContactID, TBL_ContactName.FirstName FROM TBL_ContactsList, TBL_ContactName WHERE ((TBL_ContactName.NameID != $userid) AND (TBL_ContactsList.ContactID != $userid)) AND ((TBL_ContactName.NameID IN ($UserIDAList) OR TBL_ContactName.NameID IN $UserIDBList)))");

while ($row = mysql_fetch_array($result, MYSQL_NUM)) {
    printf ("ID: %s  Name: %s", $row[0], $row[1]);
    echo "<br/>";
}

Only the SQL-Query (readability):

只有 SQL 查询（可读性）：

SELECT TBL_ContactsList.ContactID, TBL_ContactName.FirstName 
FROM TBL_ContactsList, TBL_ContactName 
WHERE ((TBL_ContactName.NameID != $userid) AND (TBL_ContactsList.ContactID != $userid)) 
AND ((TBL_ContactName.NameID IN ($UserIDAList) OR TBL_ContactName.NameID IN $UserIDBList)))

Output:

输出：

ID: 2 Name: Joe
ID: 3 Name: Joe
ID: 4 Name: Joe
ID: 2 Name: Jimbo
ID: 3 Name: Jimbo
ID: 4 Name: Jimbo
ID: 2 Name: Mike
ID: 3 Name: Mike

EDIT: Here is what I ended up using. (can't figure out indent on here.)

编辑：这是我最终使用的。（无法弄清楚这里的缩进。）

But now I am missing an entry from the db.

但现在我错过了数据库中的一个条目。

$result = mysql_query("
SELECT cl.ContactID, cn.FirstName
FROM TBL_ContactName AS cn
INNER JOIN TBL_ContactsList AS cl
ON cl.ContactID = cn.NameID
WHERE
cn.NameID != $userid
AND (
cn.NameID IN ($UserIDBList) OR cn.NameID IN ($UserIDAList)
)
"); The output looks like this.
ID: 2 Name: Joe
ID: 3 Name: Jimbo

$result = mysql_query("
SELECT cl.ContactID, cn.FirstName
FROM TBL_ContactName AS cn
INNER JOIN TBL_ContactsList AS cl
ON cl.ContactID = cn.NameID
WHERE
cn.NameID != $userid
AND (
cn.NameID IN ($UserIDBList) OR cn.NameID IN ($UserIDAList)
)
"); 输出看起来像这样。
ID：2 姓名：Joe
ID：3 姓名：Jimbo

But when I put LEFT JOIN I get this. Close but still missing ID.
ID: 2 Name: Joe
ID: 3 Name: Jimbo
ID: Name: Mike

但是当我放 LEFT JOIN 时，我明白了。关闭但仍然缺少 ID。
ID：2 姓名：Joe
ID：3 姓名：Jimbo
ID：姓名：Mike

Any ideas?? THanks!

有任何想法吗？？谢谢！

回答by Arda

If I got your SQL structure correctly, changing SQL like this should probably fix it. At least it's a proper usage.

如果我正确地得到了你的 SQL 结构，像这样改变 SQL 应该可以解决它。至少这是一个正确的用法。

$result=mysql_query("SELECT cl.ContactID, cn.FirstName FROM TBL_ContactsList cl INNER JOIN TBL_ContactName cn ON cn.NameID=cl.ContactID WHERE cn.NameID != $userid AND (CN.NameID IN ($UserIDAList) OR CL.NameID IN ($UserIDBList))");

回答by sod

You should indent and shortcut your SQL for better readability

您应该缩进和缩短 SQL 以获得更好的可读性

$result = mysql_query("
  SELECT cl.ContactID, cl.FirstName
  FROM TBL_ContactsList cl
  JOIN TBL_ContactName cn
  WHERE (
    cn.NameID != $userid AND
    cl.ContactID != $userid
  ) AND (
    cn.NameID IN ($UserIDAList) OR 
    cn.NameID IN ($UserIDBList)
  )
");

回答by Daniel Kutik

please give feedback, if this works out for you:

请提供反馈，如果这对您有用：

SELECT cl.ContactID, cn.FirstName 
  FROM TBL_ContactName AS cn 
  JOIN TBL_ContactsList as cl
    ON cn.NameID = cn.ContactID
  WHERE cn.NameID != $userid
    AND (cn.NameID IN ($UserIDAList) OR cn.NameID  IN ($UserIDBList));