如何使用JAXB从xsd生成实现Serializable接口的Java类?

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时间:2020-08-12 13:41:43  来源:igfitidea点击:

How to generate a Java class which implements Serializable interface from xsd using JAXB?

javaxsdjaxbxjc

提问by Boris Pavlovi?

I would like to introduce caching into an existing Spring project which uses JAXB to expose WebServices. Caching will be done on the level of end points. In order to do that classes generated from XSD using JAXB need to implement Serializableinterface and override Object's toString()method.

我想在现有的 Spring 项目中引入缓存,该项目使用 JAXB 来公开 WebServices。缓存将在端点级别完成。为了使用 JAXB 从 XSD 生成的类需要实现Serializableinterface 并覆盖ObjecttoString()方法。

How to instruct the xjc tool using XSD to generate source with needed properties?

如何使用 XSD 指示 xjc 工具生成具有所需属性的源代码?

采纳答案by Pascal Thivent

Serializable

可序列化

Use xjc:serializablein a custom bindings file to add the java.io.Serializableinterface to your classes along with a serialVersionUID:

使用xjc:serializable在自定义绑定文件的添加java.io.Serializable界面沿着你的类serialVersionUID

<?xml version="1.0" encoding="UTF-8"?>
<bindings xmlns="http://java.sun.com/xml/ns/jaxb"
            xmlns:xsi="http://www.w3.org/2000/10/XMLSchema-instance"
            xmlns:xjc="http://java.sun.com/xml/ns/jaxb/xjc"
            xsi:schemaLocation="
http://java.sun.com/xml/ns/jaxb http://java.sun.com/xml/ns/jaxb/bindingschema_2_0.xsd"
version="2.1">
  <globalBindings>
    <serializable uid="1" />
  </globalBindings>
</bindings> 

toString()

toString()

Use a superclass (see xjc:superClass) from which all your bound classes will inherit. This class won't be generated by xjc so you are free to create it as you please (here with a toString()implementation):

使用一个超类(请参阅 参考资料xjc:superClass),您的所有绑定类都将从该超类继承。这个类不会由 xjc 生成,所以你可以随意创建它(这里有一个toString()实现):

<?xml version="1.0" encoding="UTF-8"?>
<bindings xmlns="http://java.sun.com/xml/ns/jaxb"
                xmlns:xsi="http://www.w3.org/2000/10/XMLSchema-instance"
                xmlns:xjc="http://java.sun.com/xml/ns/jaxb/xjc"
                xsi:schemaLocation="
http://java.sun.com/xml/ns/jaxb http://java.sun.com/xml/ns/jaxb/bindingschema_2_0.xsd"
    version="2.1">
    <globalBindings>
        <serializable uid="1" />
        <xjc:superClass name="the.package.to.my.XmlSuperClass" />
    </globalBindings>
</bindings>

回答by artspb

Another way to generate toString()method - JAXB2 Basics Plugins. This way looks better because doesn't use reflection. Example how to do it with maven below.

另一种生成toString()方法的方法 - JAXB2 Basics Plugins。这种方式看起来更好,因为不使用反射。示例如何在下面使用 maven 执行此操作。

<build>
    <plugins>
        <plugin>
            <groupId>org.jvnet.jaxb2.maven2</groupId>
            <artifactId>maven-jaxb2-plugin</artifactId>
            <version>0.8.2</version>
            <executions>
                <execution>
                    <goals>
                        <goal>generate</goal>
                    </goals>
                </execution>
            </executions>
            <configuration>
                <schemaDirectory>
                    ${project.basedir}/src/main/resources
                </schemaDirectory>
                <generateDirectory>
                    ${project.basedir}/src/main/java
                </generateDirectory>
                <extension>true</extension>
                <args>
                    <arg>-XtoString</arg>
                </args>
                <plugins>
                    <plugin>
                        <groupId>org.jvnet.jaxb2_commons</groupId>
                        <artifactId>jaxb2-basics</artifactId>
                        <version>0.6.4</version>
                    </plugin>
                </plugins>
            </configuration>
        </plugin>
    </plugins>
</build>

<dependencies>
    <dependency>
        <groupId>org.jvnet.jaxb2_commons</groupId>
        <artifactId>jaxb2-basics-runtime</artifactId>
        <version>0.6.4</version>
    </dependency>
</dependencies>

As the result you'll get such code.

结果你会得到这样的代码。

public String toString() {
    final ToStringStrategy strategy = JAXBToStringStrategy.INSTANCE;
    final StringBuilder buffer = new StringBuilder();
    append(null, buffer, strategy);
    return buffer.toString();
}

public StringBuilder append(ObjectLocator locator, StringBuilder buffer, ToStringStrategy strategy) {
    strategy.appendStart(locator, this, buffer);
    appendFields(locator, buffer, strategy);
    strategy.appendEnd(locator, this, buffer);
    return buffer;
}

public StringBuilder appendFields(ObjectLocator locator, StringBuilder buffer, ToStringStrategy strategy) {
    {
        String theName;
        theName = this.getName();
        strategy.appendField(locator, this, "name", buffer, theName);
    }
    {
        String theBank;
        theBank = this.getBank();
        strategy.appendField(locator, this, "bank", buffer, theBank);
    }
    return buffer;
}

回答by vikingsteve

This worked for me:

这对我有用:

<?xml version="1.0" encoding="UTF-8"?>
<jaxb:bindings xmlns:jaxb="http://java.sun.com/xml/ns/jaxb" xmlns:xjc="http://java.sun.com/xml/ns/jaxb/xjc" jaxb:version="2.1">
    <jaxb:globalBindings>
        <xjc:serializable uid="1337"/>
    </jaxb:globalBindings>
</jaxb:bindings>

回答by BERGUIGA Mohamed Amine

i use this code and is work for me

我使用此代码并且对我有用

<?xml version="1.0" encoding="UTF-8"?>
<jaxb:bindings xmlns:jaxb="http://java.sun.com/xml/ns/jaxb" xmlns:xjc="http://java.sun.com/xml/ns/jaxb/xjc" jaxb:version="2.1">
    <jaxb:globalBindings>
        <xjc:serializable uid="1"/><!--If you Forgot this line your class did not be serializable--!>
    </jaxb:globalBindings>
</jaxb:bindings>

回答by Gio

in order to get interface Serializable add following binding information to the xsd-file:

为了获得接口 Serializable,将以下绑定信息添加到 xsd 文件中:

<?xml version="1.0" encoding="UTF-8"?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:jaxb="http://java.sun.com/xml/ns/jaxb" jaxb:version="2.0"> <xs:annotation> <xs:appinfo> <jaxb:globalBindings optionalProperty="primitive"> <jaxb:serializable/> </jaxb:globalBindings> </xs:appinfo> </xs:annotation><xs:element name="myXsdElement"> ..... </xs:element> </xs:schema>

<?xml version="1.0" encoding="UTF-8"?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:jaxb="http://java.sun.com/xml/ns/jaxb" jaxb:version="2.0"> <xs:annotation> <xs:appinfo> <jaxb:globalBindings optionalProperty="primitive"> <jaxb:serializable/> </jaxb:globalBindings> </xs:appinfo> </xs:annotation><xs:element name="myXsdElement"> ..... </xs:element> </xs:schema>

回答by Jacques Koorts

And here is a sample using CXF 3.1.10. Remember to include compile group: 'org.apache.cxf.xjc-utils', name: 'cxf-xjc-runtime', version: '3.1.0'

这是使用 CXF 3.1.10 的示例。记得包含编译组:'org.apache.cxf.xjc-utils',名称:'cxf-xjc-runtime',版本:'3.1.0'

<jxb:bindings 
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:jxb="http://java.sun.com/xml/ns/jaxb"
version="2.1">

<jxb:bindings schemaLocation="META-INF/wsdl/xsd2.xsd">

        <jxb:globalBindings xmlns:jxb="http://java.sun.com/xml/ns/jaxb" xmlns:xs="http://www.w3.org/2001/XMLSchema">
                <jxb:serializable uid="1"/>
              </jxb:globalBindings>