Python Django ModelForm 有一个隐藏的输入
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/15795869/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Django ModelForm to have a hidden input
提问by Modelesq
So I have my TagStatus model. I'm trying to make a ModelForm for it. However, my form requires that the hidden input be populated with the {{ tag.name }}. I've been looking through the docs and I don't know how to make the tag field a hidden input. Perhaps a ModelForm isn't the way to go?
所以我有我的 TagStatus 模型。我正在尝试为它制作一个 ModelForm。但是，我的表单要求使用 {{ tag.name }} 填充隐藏的输入。我一直在查看文档，但不知道如何使标签字段成为隐藏输入。也许 ModelForm 不是要走的路？
models.py:
模型.py：
class TagStatus(models.Model):
user = models.ForeignKey(User, null=True, unique=True)
status = models.CharField(max_length=2, choices=tag_statuses)
tag = models.ForeignKey(Tag, null=True, blank=True)
def __unicode__(self):
return self.status
def save(self, *args, **kwargs):
super(TagStatus, self).save(*args, **kwargs)
class TagStatusForm(modelForm):
class Meta:
model = TagStatus
fields = ('status','tag')
widgets = {
'select': Select,
'tag': ???
}
django views.py:
Django 视图.py：
@login_required
def tags(request):
all_tags = Tag.objects.all()
context = base_context(request)
if request.method == 'POST':
if 'status_check' in request.POST:
status_form = TagStatusForm(request.POST)
#if request.is_ajax():
if status_form.is_valid():
status_form.save()
response = simplejson.dumps({"status": "Successfully changed status"})
else:
response = simplejson.dumps({"status": "Error"})
return HttpResponse (response, mimetype='application/json')
status_form = TagStatusForm()
context['status_form'] = status_form
context['all_tags'] = all_tags
return render_to_response('tags/tags.html', context, context_instance=RequestContext(request))
template:
模板：
{% for tag in all_tags %}
....
<form class="nice" id="status-form" method="POST" action="">
{% csrf_token %}
<input type="hidden" name="status_check" />
<input type='hidden' name="tag" value="{{ tag.name }}" />
{{ status_form.status }}
</form>
...
{% endfor %}
How would I go about making a hidden input through a django ModelForm and then populate it through the template?
我将如何通过 django ModelForm 进行隐藏输入，然后通过模板填充它？
采纳答案by Josh
To make a field in a ModelField a hidden field, use a HiddenInput widget. The ModelForm uses a sensible default widget for all the fields, you just need to override it when the object is constructed.
要将 ModelField 中的字段设为隐藏字段，请使用 HiddenInput 小部件。ModelForm 为所有字段使用一个合理的默认小部件，您只需要在构造对象时覆盖它。
class TagStatusForm(forms.ModelForm):
class Meta:
model = TagStatus
widgets = {'tag': forms.HiddenInput()}
回答by Srikar Appalaraju
There are 3 possible ways (AFAIK) to render hidden fields in Django -
有 3 种可能的方法 (AFAIK) 在 Django 中呈现隐藏字段 -
1.You could declare a field normally in forms.pybut in your templates html file use {{ form.field.as_hidden }}
1.您可以正常声明一个字段，forms.py但在您的模板html文件中使用{{ form.field.as_hidden }}
2.in forms.pydirectly use hidden input widget.
2.在forms.py直接使用隐藏输入小部件。
class MyForm(forms.Form):
hidden_field = forms.CharField(widget=forms.HiddenInput())
Once you make the field a hidden input, you could populate the value of the field in templates. Now your hidden field is ready for rendering.
一旦您将该字段设为隐藏输入，您就可以在模板中填充该字段的值。现在您的隐藏字段已准备好进行渲染。
3.Regular form equivalent (thanks to @Modelesq for sharing this nugget). Here no Django is involved. Changes are done at HTML template level. <input type="hidden" name="tag" value="{{ tag.name }}" />
3.等价的正则形式（感谢@Modelesq 分享这个金块）。这里不涉及 Django。更改是在 HTML 模板级别完成的。<input type="hidden" name="tag" value="{{ tag.name }}" />
回答by Lucas B
I was looking for a way to HIDE ALL INPUTS :
我正在寻找一种隐藏所有输入的方法：
class TagStatusForm(forms.ModelForm):
class Meta:
model = TagStatus
def __init__(self, *args, **kwargs):
super(TagStatusForm, self).__init__(*args, **kwargs)
for field in self.fields:
self.fields[field].widget = forms.HiddenInput()
回答by dfrankow
I posted a way to do it with generic class-based views here:
我张贴的方式与普通的基于类的意见做这里：
from django.forms import HiddenInput
from django.forms.models import modelform_factory
_patient_create_form = modelform_factory(
models.Patient,
fields=['name', 'caregiver_name', 'sex', 'birth_date',
'residence', 'country'],
widgets={'country': HiddenInput()})
class PatientCreate(LoginRequiredMixin, UserOrgRequiredMixin, CreateView):
form_class = _patient_create_form
template_name = 'healthdbapp/patient_form.html'
